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3 years ago

Combine like terms to create an equivalent expression. 20(-15r+0.75)

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

5 0

Answer:

-300r + 15

Step-by-step explanation:

Hope this helps!

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7+n=−5 18=−3y−6 3/5x=18

Keith_Richards [23]

Answer:

1) n=-12

2) y=-8

3) x= 1/30

Step-by-step explanation:

1) 7+n=-5

7+n-7=-5-7

n=-12

2) 18=-3y-6

-3y-6=18

-3y-6+6=18+6

-3y=24

-3y/-3 = 24/-3

y= -8

3) 3/5x=18

3/15 X 5x= 18 X 5x

3=90x

90x/90= 3/90

x= 1/30

8 0

3 years ago

Read 2 more answers

Marissa bought x shirts that cost $19.99 each and y pairs of shorts that cost $14.99 each. The next day she went back to the sto

zlopas [31]

Answer:

Step-by-step explanation:

Step one:

given data

day one

x shirts that cost $19.99 each and

y pairs of shorts that cost $14.99 each.

Day two

3 more shirts that cost $19.99 each and

4 more pairs of shorts cost $14.99 each.

Step two:

the total number of shirts is

x+3

and the total number of shorts is

y+4

The total cost is ex[ressed as

19.99(x+3)+ 14.99(y+4)

7 0

3 years ago

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Ellis multiplies the dimensions of a rug on a drawing by a scale factor to find the dimensions of the actual rug. The dimensions

Digiron [165]

2 * 18 = 36
3 * 18 = 54
so ur scale factor is 18

5 0

3 years ago

Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the

VikaD [51]

In general, the exponential growth function is given by the formula below

$f(x)=a(1+r)^x$

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

$\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}$

And 1976 is n=16

$\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}$

Solve the two equations simultaneously, as shown below

$\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}$

Solving for a,