Resistance of a lightbulb is 240.8 ohm
Given:
Power = 120 W
Frequency = 60.0-Hz
Voltage = 170 V
To Find:
Resistance of a lightbulb
Solution: The electrical resistance of a circuit is the ratio between the voltage applied to the current flowing through it. Rearranging the above relation, R = V I. The unit of electrical resistance is ohms.
The resistance of the light bulb is given by the formula, R=V²/P
R = (170)^2/120
R = 240.8 ohm
Hence, the resistance of light bulb is R = 240.8 ohm
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Answer:
1. K.E = 11.2239 kJ ≈ 11.224 kJ
2.
3.
Solution:
Now, the kinetic energy of an ideal gas per mole is given by:
K.E =
where
m = no. of moles = 3
R = Rydberg's constant = 8.314 J/mol.K
Temperature, T = 300 K
Therefore,
K.E =
K.E = 11223.9 J = 11.2239 kJ ≈ 11.224 kJ
Now,
The heat capacity at constant volume is:
Now,
Required heat transfer to raise the temperature by is:
Answer:
F=-100N; a=1.3m/s^2
Explanation:
Force is being made by student, so wall counteracts that force by not moving so it is equally opposite.
Yes, they are synonymous terms.
Answer:
The beetles consume the trees as food. So, if the trend continues, it’s likely that the trees will die out in the coming years
Explanation: