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3 years ago

14

where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the work

place?

1 answer:

goldenfox [79]3 years ago

8 0

Answer:

Both

Explanation:

You might be interested in

How many electrons can possess this set of quantum numbers: principal quantum number n = 4, magnetic quantum number mℓ = −1?

LekaFEV [45]

Answer:

6 electrons

Explanation:

To solve this question lets determine the possible quantum numbers for the principal quantum number n = 4.

For the quantum number l which describes the shape of the orbital, we have the possible values : 0 to n-1.

Thus, for n = 4 the l can assume the values 0, 1, 2, 3 ( 4 possible shapes )

For the angular quantum number, ml, which tell us the orientation in space,we have the values - l to + l.

So lets determine the number of orbials which can have the values -l for n=4

l = 0 ml = 0

l= 1 ml = -1,0,1

l= 2 ml = -2, -1, 0, 1, 2

l= 3 ml = -3,-2,-1,0,1,2,3

So we have three orbital with ml = - 1 and from Pauli´s exclusion principle we can have up two electrons in each orbital. Thus for n= 4 we can have up to 6 electrons with ml = -1

3 0

3 years ago

What are the three categories of adult development?

andreev551 [17]

Physical development , Cognitive Development , psychosocial development I think!

5 0

4 years ago

Human reaction times are worsened by alcohol. How much further (in feet) would a drunk driver's car travel before he hits the br

sweet-ann [11.9K]

Answer:

A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes

Explanation:

Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

where,

Vf = Final Velocity of Car = 0 mi/h

Vi = Initial Velocity of Car = 50 mi/h

a = deceleration of car

s = distance covered

Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.

So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:

s = vt

FOR SOBER DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 0.33 s

s = s₁

Therefore,

s₁ = (73.33 ft/s)(0.33 s)

s₁ = 24.2 ft

FOR DRUNK DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 1 s

s = s₂

Therefore,

s₂ = (73.33 ft/s)(1 s)

s₂ = 73.33 ft

Now, the distance traveled by drunk driver's car further than sober driver's car is given by:

ΔS = s₂ - s₁

ΔS = 73.33 ft - 24.2 ft

<u>ΔS = 49.13 ft</u>

6 0

3 years ago

during a dodge ball game a student throw a ball at another player what forces act on the ball as it flie through the air

olchik [2.2K]

Gravity acts to accelerate the ball downward, and air resistance acts in a way to slow the ball along it's instantaneous velocity (no matter which way it's moving air applies a force in the opposite direction)

5 0

4 years ago

Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, t

kkurt [141]

Answer:

$t=0.038s$

Explanation:

Project mass m=3.8 kg

Initial speed vi= 0m/s

Final speed vf= 9.3×10³ m/s

Force F=9.3×10⁵N

To find

Time t

Solution

From Newtons second law we know that

∑F=ma

Where m is mass

a is acceleration

We can write this equation as

∑F=m(Δv/Δt)

$=m\frac{v_{f}-v_{i}}{t}$

Rearrange this equation to find time t

So

$t=m\frac{v_{f}-v_{i}}{F}$

Substitute the given values

$t=3.8kg\frac{9.3*10^3m/s-0}{9.3*10^5N} \\t=0.038s$

5 0

3 years ago