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Agata [3.3K]
3 years ago
5

using newtons law a force of 250N is applied to an object that accelerates at a rate of 5M/s2 what is the mass of the object?

Physics
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

50 kg

Explanation:

F = ma

250 N = m (5 m/s²)

m = 50 kg

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A runner has a speed of 5m/s and a mass of 130 kg what is his kinetic energy?
arlik [135]
M= 130 kg

v= 5 m/s

kinetik energy = ½• m•v²


= ½ • 130• 5²
= ½•130•25
= ½•3250
= 1625.
4 0
3 years ago
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A train moving at a constant speed of 50.0 km/h moves east for 45.0 min, then in a direction 45.0° east of due north for 10.0 mi
Yuki888 [10]

Answer:

3.47km/h with a direction of 67.8 degrees north of west.

Explanation:

First we need to calculate the displacement on the X axis, so:

d_{x1}=50.0km/h*45min(\frac{1h}{60min})=37.5km\\d_{x2}=50.0km/h*10min(\frac{1h}{60min})*cos(45^o)=5.90km\\d_{x1}=-50.0km/h*55.0min(\frac{1h}{60min})=45.8km\\D_x=37.5+5.90-45.8=-2.4km

then on the Y axis:

D_y=50.0km/h*10min(\frac{1h}{60min})*sin(45^o)=5.90km

The magnitud of the displacement is given by:

D=\sqrt{D_x^2+D_y^2} \\D=6.37km

and the angle:

\alpha =arctg(\frac{5.90}{2.41})=67.8^o

that is 67.8 degrees north of west.

v=\frac{D}{t}\\v=\frac{6.37km}{110min*\frac{1h}{60min}}\\v=3.47km/h

8 0
3 years ago
Your car's 30.0 W headlight and 2.50 kW starter are ordinarily connected in parallel in a 12.0 V system. What power (in W) would
Tatiana [17]

Answer:

<h3>The power of headlight in series connection is 29.64 W</h3>

Explanation:

Given :

Power of headlight P_{1} = 30 W

Power of starter P_{2} = 2500 W

Voltage of headlight and starter V = 12 V

From equation of power,

 P = \frac{V^{2} }{R}

 R = \frac{V^{2} }{P}

For finding the resistance of headlight and starter,

⇒ For headlight,

 R_{1}  = \frac{144}{30} = 4.8 Ω

⇒ For starter,

R_{2} = \frac{144}{2500} = 0.057 Ω

Since equivalent resistance,

R_{eq} = R_{1} + R_{2} + ........

R_{eq} = 4.8 +0.057 = 4.857 Ω

So power in series is given by,

 P_{s } = \frac{V^{2} }{R_{eq} }  = \frac{144}{4.857}

 P_{s } = 29.64 W

8 0
3 years ago
A space expedition discovers a planetary system consisting of a massive star and several spherical planets. The planets all have
Juliette [100K]

Answer:

T/√8

Explanation:

From Kepler's law, T² ∝ R³ where T = period of planet and R = radius of planet.

For planet A, period = T and radius = 2R.

For planet B, period = T' and radius = R.

So, T²/R³ = k

So, T²/(2R)³ = T'²/R³

T'² = T²R³/(2R)³

T'² = T²/8

T' = T/√8

So, the number of hours it takes Planet B to complete one revolution around the star is T/√8

7 0
3 years ago
Describe how the three methods of thermal energy transfer may take place within the iguana’s enclosure.
sasho [114]

Answer:

Heat can travel from one place to another in three ways: Conduction, Convection and Radiation. Both conduction and convection require matter to transfer heat.  Conduction is the transfer of heat between substances that are in direct contact with each other. Thermal energy is transferred from hot places to cold places by convection. Radiation is a method of heat transfer that does not rely upon any contact between the heat source and the heated object as is the case with conduction and convection. Heat can be transmitted through empty space by thermal radiation often called infrared radiation.

Explanation:

6 0
2 years ago
Read 2 more answers
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