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JulijaS [17]
2 years ago
7

Look at the variables for this lab. Which variable would we have to change in order to change the amount of current flowing thro

ugh the wire?
Physics
1 answer:
____ [38]2 years ago
3 0
Where are the variables from the lab?
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Which describes acceleration involving only a change in direction?
Viefleur [7K]
If we consider any system moving with u<span>niform circular motion we can notice that the MAGNITUDE of the accelaration remains constant. However,  there is a change in the direction of the acceleration at every instant of time .

 As the object moves through the circle the acceleration changes its direction always pointing to the center of the circle.</span>
6 0
3 years ago
When an object experiences centripetal acceleration, in which direction does it accelerate?
tatuchka [14]

Centripetal acceleration points from the object toward the center of the circular path it's traveling.

3 0
3 years ago
Read 2 more answers
the electrical resistance of copper wire varies directly with its length and inversely with the square of the diameter of the wi
leonid [27]

Answer:24.47

Explanation:

Given

L_1=30 m

d_1=3 mm

R_1=25 \Omega

L_2=40 m

d_2=3.5 mm

we know Resistance R=\frac{\rho L}{A}

Where R=resistance

\rho =resistivity

L=Length

A=area of cross-section

A=\frac{\pi d^2}{4}

Thus R\propto \frac{L}{d^2}

therefore

R_1\propto \frac{L_1}{d_1^2}--------1

R_2\propto \frac{L_2}{d_2^2}--------2

divide 1 and 2 we get

\frac{R_1}{R_2}=\frac{L_1}{L_2}\times \frac{d_2^2}{d_1^2}

\frac{R_1}{R_2}=\frac{30}{40}\times \frac{3.5^2}{3^2}

R_2=25\times 0.734\times 1.33

R_2=24.47 \Omega

8 0
3 years ago
an object is thrown into the air with an initial velocity of 12 meters per seconds from a platform that is raised 4 meters above
butalik [34]

Answer:

1.52 seconds

Explanation:

Step 1: identity the given parameters

Initial velocity (u) = 12m/s

Height above ground (h1) = 4m

Final velocity (V) = 0

Step 2: calculate the height travelled by the object from 4m height (h2).

V^2 = U^2 -2gh

0= 12^2-2(9.8*h)

2(9.8*h) = 12^2

19.6*h = 144

h = 144/19.6

h = 7.347 m

Total height above ground (ht) = 4m +7.347m = 11.347m

Step 3: calculate the time reach ground

T = √(2h/g)

T = √(2*11.347/9.8)

T= √(22.694/9.8)

T= √2.316

T= 1.52 seconds

8 0
3 years ago
5.
lesantik [10]

Answer:

It is B

it is called a jumper cable because it jumps the power from one car to the other

3 0
3 years ago
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