Am I right? Please tell me

Mathematics

1 answer:

Musya8 [376]3 years ago

4 0

Answer:

Your wrong

Step-by-step explanation:

Move the bad to the good and move the last one in the good section to bad

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If a b c=0, but abc don't equal 0, then a^2/bc b^2/ca c^2/ab=

goblinko [34]

$\sf a + b + c = 0\\abc \neq 0\\\\ \frac{a^2}{bc} + \frac{b^2}{ac} + \frac{c^2}{ab} = \frac{a^3+b^3+c^3}{abc} \\\\\sf Formula: \\a^3 + b^3 + c^3 = (a + b + c) (a^2 + b^2 + c^2- ab - bc - ca) + 3abc\\\\\frac{a^3+b^3+c^3}{abc}= \frac{(a + b + c) (a^2 + b^2 + c^2- ab - bc - ca) + 3abc}{abc}\\\\\sf However, ~a+b+c = 0. ~So:\\\\\frac{0 (a^2 + b^2 + c^2- ab - bc - ca) + 3abc}{abc}\\\\\sf Multiply~ anything ~by~ 0, ~and~ you ~get~ 0. ~So~ simplifying:\\\\\frac{3abc}{abc} = \boxed{3}$

Your final answer is 3.

3 0

3 years ago

The length of a rectangle is 8 more than its breadth. If the perimeter of a rectangle is 84 cm. Find the dimensions of the recta

tiny-mole [99]

Step-by-step explanation:

84 = 2(l+b)

L+b = 84 / 2

L+b = 42

There fore..

Length is 42 and breadth is 42 - 8

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3 years ago