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3 years ago

Please help and thank you

Mathematics

1 answer:

ivann1987 [24]3 years ago

7 0

First, let's try to isolate x to make the question easier to solve.

|2x-6|≤6

2x - 6 ≤ 6

2x - 6 ≥ -6

2x ≤ 12

x ≤ 6

2x ≥ 0

x ≥ 0

Knowing this, the graph should be equal or less than 6 and equal or greater than 0, making Option D the correct answer.

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How much does 5 pounds for $2.49 equal

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1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat

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Answer:

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Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) $f(x) = 6x + 6/x$

$f\prime(x) = 6 - 6/x^2 = 0$ and $x \neq 0$

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The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum.

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$f\prime(x)=4/x^2-4/x^3=0$ and $x \neq 0$

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The function is decreasing on the interval (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum.

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So the roots are $x = 0$ and $x = 8$

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The function is decreasing on the interval [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum.

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$f\prime(x) = 4/(x-2)^{1/3}$ has no solution and $x = 2$ is crtitical point.

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The function is decreasing on the interval (-∞,2]

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