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2 years ago

2. An atom of Be has four protons, five neutrons and four electrons. What 10 poin

Chemistry

1 answer:

Goryan [66]2 years ago

7 0

Answer:

Five ( 5 ) is the correct answer

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NH3 + H2SO4 → __(NH4)2SO4

Zielflug [23.3K]

Answer:

This is not a balanced equation

Explanation:

Let's make it a balanced equation.

2 NH3 + H2So4 = (NH4)2So4

Glad I could help!!

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3 years ago

How is sound energy produced? A. by vibrating objects B. by stationary objects C. by temperature differences D. by objects being

viva [34]

Sound energy is produced by vibrating objects.

Example: when you speak you vibrate the air molecules in the air. If you where to speak in space no “sound” would be produced since there is nothing for the vibration of your voice to travel through.

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3 years ago

Read 2 more answers

chemistry moles PLEASE HELP!! A package of foil weighs 360g. How many moles of aluminium are there in this package??

Ksenya-84 [330]

Answer:

I am not 100% sure but I think it is 26.981538

Explanation:

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2 years ago

Determine the frequency of light with a wavelength of 4.50 x 10-7 m.

jeyben [28]

The frequency of a photon of red light with wavelength 4.50 x 10−7m is 6.67 x 1014Hz

4 0

2 years ago

Tellurium has eight isotopes: Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), T

Elena-2011 [213]

The average atomic mass of tellurium, calculated from its eight isotopes (Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), Te-128 (31.79%), and Te-130 (34.48%)) is 127.723 amu.

The average atomic mass of Te can be calculated as follows:

$A = m_{Te-120}\%_{Te-120} + m_{Te-122}\%_{Te-122} + m_{Te-123}\%_{Te-123} + m_{Te-124}\%_{Te-124} + m_{Te-125}\%_{Te-125} + m_{Te-126}\%_{Te-126} + m_{Te-128}\%_{Te-128} + m_{Te-130}\%_{Te-130}$

Where:

m: is the mass

%: is the abundance percent

Knowing all the masses and abundance values, we have:

$A = 120*0.09\% + 122*2.46\% + 123*0.87\% + 124*4.61\% + 125*6.99\% + 126*18.71\% + 128*31.79\% + 130*34.48\%$

To find the average atomic mass we need to change all the percent values to decimal ones

$A = 120*9 \cdot 10^{-4} + 122*2.46 \cdot 10^{-2} + 123*8.7\cdot 10^{-3} + 124*4.61 \cdot 10^{-2} + 125*6.99\cdot 10^{-2} + 126*0.1871 + 128*0.3179 + 130*0.3448 = 127.723$

Therefore, the average atomic mass of tellurium is 127.723 amu.

You can find more about average atomic mass here brainly.com/question/11096711?referrer=searchResults

I hope it helps you!

4 0

2 years ago