Question

Mass of 0.432 moles of C8H9O4?

Answer 1

Find one mole
8 C = 8 * 12 = 96
9 H = 1 * 9 = 9
4 O = 4 *16 = 64
Total = 169 

1 mol = 169 grams.
0.432 mol = x

1/0.432 = 169/x
x = 0.432 * 169
x = 73.0 grams

Answer 2

Explanation:

It is known that number of moles present in a substance is equal to the mass divided by molar mass.

Mathematically,      No. of moles = $\frac{mass}{\text{molar mass}}$

As it is given that number of moles are 0.432 moles and molar mass of $C_{8}H_{9}O_{4}$ is 169.15 g/mol.

Hence, calculate the mass of $C_{8}H_{9}O_{4}$ is as follows.

                 No. of moles = $\frac{mass}{\text{molar mass}}$

                     0.432 mol = $\frac{mass}{169.15 g/mol}$

                         mass = 73.072 g

Thus, we can conclude that the mass of 0.432 moles of $C_{8}H_{9}O_{4}$ is 73.072 g.