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Len [333]
3 years ago
6

Mass of 0.432 moles of C8H9O4?

Chemistry
2 answers:
Fiesta28 [93]3 years ago
7 0
Find one mole
8 C = 8 * 12 = 96
9 H = 1 * 9 = 9
4 O = 4 *16 = 64
Total = 169 

1 mol = 169 grams.
0.432 mol = x

1/0.432 = 169/x
x = 0.432 * 169
x = 73.0 grams
romanna [79]3 years ago
4 0

Explanation:

It is known that number of moles present in a substance is equal to the mass divided by molar mass.

Mathematically,      No. of moles = \frac{mass}{\text{molar mass}}

As it is given that number of moles are 0.432 moles and molar mass of C_{8}H_{9}O_{4} is 169.15 g/mol.

Hence, calculate the mass of C_{8}H_{9}O_{4} is as follows.

                 No. of moles = \frac{mass}{\text{molar mass}}

                     0.432 mol = \frac{mass}{169.15 g/mol}

                         mass = 73.072 g

Thus, we can conclude that the mass of 0.432 moles of C_{8}H_{9}O_{4} is 73.072 g.

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Answer:

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The equation below shown the reaction between the enthalpy of reaction at a particular temperature to another.

\delta H^0__{R,T_2} = \delta H^0__{R,T_1} } + \int\limits^{T_2}_{T_1} {\delta C_p(T')} \, dT'

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