All categories

2 years ago

Evaluate g(x)=4 -3x when x=-3,0, and 5

Mathematics

1 answer:

4vir4ik [10]2 years ago

6 0

Answer:

-11

Step-by-step explanation:

You might be interested in

Solve 50r − 6 = 82r − 70

Basile [38]

Answer:

Step-by-step explanation: 50r - 6= 82r-70

Add 50r to 82r which equals to 132 r

Now add the the 70 to the left side so -6+70 should equal 76.

Now it should look like this 76=132r

To get the value of r you have to divide 76/132 on both sides of the equation and your answer should be 0.57=r

6 0

2 years ago

Read 2 more answers

The area of the trapezoid

ELEN [110]

Answer:

Step-by-step explanation:

The formula of an area of a trapezoid:

$A=\dfrac{b_1+b_2}{2}\cdot h$

b₁, b₂ - bases

h - height

We have b₁ = 10in, b₂ = 5in and h = 11in. Substitute:

$A=\dfrac{10+5}{2}\cdot11=\dfrac{15}{2}\cdot11=7.5\cdot11=82.5\ in^2$

7 0

3 years ago

Read 2 more answers

A manufacturer knows that 9% of the products it produces are defective. Find the probability that among 6 randomly selected prod

Advocard [28]

Answer:1%

Step-by-step explanation:

3 0

3 years ago

In 2013 approximately 1.6 million students took the critical reading portion of the sat exam the mean score modal score and the

Citrus2011 [14]

Onions are good for you !! :)))

6 0

3 years ago

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$

When t = 0, N = 400

$400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325$

When t = 3, N = 650

$650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49$

The equation for the population becomes:

$N = 725 - 325 e^{-0.49t}$

At t = 5, the population becomes:

$N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697$

N(5) = 700 ( to the nearest 50)

6 0

3 years ago