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shutvik [7]
3 years ago
6

2 3/8 • 1 1/6 Help step sis I'm stuck

Mathematics
2 answers:
NeX [460]3 years ago
8 0
The person above me answer this
svlad2 [7]3 years ago
6 0

Answer:

2.77083333333

Step-by-step explanation:

I assume. Do not hold me account for mistakes, I apologize if my work is incorrect. Have a good day/night :}

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Double the sum of a number w and 3
Genrish500 [490]

Answer:

(w+3)2

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

7 0
3 years ago
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A pizza parlor offers pizzas with diameters of 8 in, 10 in, and 12 in. find the area of each size pizza. round to the nearest te
leonid [27]
The best buy is the in. I really hope this helped
4 0
3 years ago
If 6 times a number is added to -4, the result is 10 times the number. Find the number.
andrew11 [14]

the number is - 1

let the number be n then 6 times the number is 6n and added to -4 is

- 4 + 6n = 10n ( equal to 10 times the number )

subtract 6n from both sides

- 4 = 4n ( divide both sides by 4 )

\frac{-4}{4} = n , hence n = - 1


5 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
If one factor of 6.x2 + 5x – 6 is
sattari [20]
C. 2x + 3

You have many ways to solve this!
You could...

A) multiply all the answer choices by 3x-2 and see what matches

B) Factor the trinomial

C) Divide the trinomial by the binomial using long division
7 0
3 years ago
Read 2 more answers
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