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2 years ago

Find missing side then find perimeter Brainiest answer to whoever is first

Mathematics

1 answer:

Alik [6]2 years ago

5 0

Answer:

look down

Step-by-step explanation:

the missing side is $\sqrt{52}$ so the perimeter is 34+2 $\sqrt{13}$

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Elis [28]

Answer:

Step-by-step explanation:

36 divided by 4 is 9

5 0

3 years ago

Read 2 more answers

Asap, sorry the pics kinda blurry

Vadim26 [7]

Here is all the work with it

3 0

2 years ago

you deposit 1000 in savings account that earns .5% each month assuming you do not deposit or withdraw any money from the account

ikadub [295]

Answer:

$1015.11

Step-by-step explanation:

Compounded interest rate formula: A = P(1 + r/n)^t

Step 1: Plug in known variables

A = 1000(1 + 0.005/12)^36

Step 2: Multiply it all together

1000(1.00042)^36

1000(1.01511)

1015.11

This is a pretty bad bank considering only giving you .5% interest per month.

7 0

3 years ago

Prove that an = 4^n + 2(-1)^nis the solution to

olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute $a_n=4^n+2(-1)^n$ in the equation $a_n=3a_{n-1}+4a_{n-2}$ the equality is true.

Let's substitute first in the right hand side:

$3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})$

Now we use the distributive laws. Also, note that $(-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n}$ (this also works when the power is n-2).

$=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}$

$=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}$

$=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n$

then the sequence solves the recurrence relation.

4 0

3 years ago

A coin is tossed 20 times. It lands heads four times. Compare the experimental probability to its theoretical probability. If th

MrRa [10]

Theoretical probability is based on the likelihood of events.

if a coin is flipped 20 times, and it has landed on heads 4 times, theres a 50% chance it would land on heads the 5th time.

it could be that heads gets more than tails or it could be vise versa.

The probability of getting two heads is 1 in 4.

5 0

3 years ago