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3 years ago

Question 2

1 answer:

5 0

Your answer would be c and d because coefficients are the numbers that go in front of the variables. Have a nice day I hope this helped :)

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Rufus works an average of 46 hours each week. He gets paid $5.70 per

fenix001 [56]

The answer is A. $14,523.60

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3 years ago

30 secs on battery hurry for brainles

labwork [276]

Answer:

$8\frac{1}{2}$

Step-by-step explanation:

$\frac{17}{2}=$ $8\frac{1}{2}$

17 ÷ 2 = 8.5

8.5 as a mixed number is $8\frac{1}{2}$ .

3 0

3 years ago

Read 2 more answers

(X-2)²+(y-1)²=25 how do you do this problem?

Tasya [4]

$(x-x_c)^2+(y-y_c)^2=r^2\\
(x_c,y_c) - \text{center}\\\\
(x-2)^2+(y-1)^2=25\\
\text{center}=(2,1)\\
r=\sqrt{25}=5$

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3 years ago

For the following exercises, evaluate the expressions, given functions f, g, and h:

sertanlavr [38]

Answer:

- 16

Step-by-step explanation:

Evaluate f(2) by substituting x = 2 into f(x) , that is

f(2) = 3(2) - 3 = 6 - 3 = 3

Evaluate g(- 1) by substituting x = - 1 into g(x) , that is

g(- 1) = 8 - (- 1)² = 8 - 1 = 7

Thus

4f(2) - 4g(- 1)

= 4(3) - 4(7)

= 12 - 28

= - 16

7 0

3 years ago

Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u

cestrela7 [59]

Answer:

The amount of nuclear fuel required is 1.24 kg.

Step-by-step explanation:

From the principle of mass energy equivalence we know that energy generated by mass 'm' in an nuclear plant is

$E=m\cdot c^2$

where

'c' is the speed of light in free space

Since the power plant operates at 1200 MW thus the total energy produced in 1 year equals

$E=1200\times 10^6\times 3600\times 24\times 365=3.8\times 10^{16}Joules$

Thus using the energy produced in the energy equivalence we get

$3.8\times 10^{16}=mass\times (3\times 10^{8})^2\\\\\therefore mass=\frac{3.8\times 10^{16}}{9\times 10^{16}}=0.422kg$

Now since the efficiency of conversion is 34% thus the fuel required equals

$mass_{required}=\frac{0.422}{0.34}=1.24kg$

8 0

3 years ago