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3 years ago

Tell me the answer for each box

Mathematics

1 answer:

4vir4ik [10]3 years ago

8 0

Answer:

if its of 15 than it would be a tip of 3 dollars and a tax of 1.35 $

Step-by-step explanation:

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X + 18 greater than or equals 26

cricket20 [7]

Answer:

x + 18 ≥ 26

Step-by-step explanation:

"greater than or equals": ≥

x + 18 ≥ 26 is your answer.

If you are trying to solve it so you isolate x, subtract 18 from both sides:

x + 18 (-18) ≥ 26 (-18)

x ≥ 26 - 18

x ≥ 8

x ≥ 8 is your answer.

5 0

3 years ago

Read 2 more answers

Dalia bought a few swirl marbles and divided it equally among four of her friends and her brother, Jake. While playing, Jake los

Licemer1 [7]

Answer:

45÷5=9-2=7 is this the equation took so long but got the right answer

3 0

4 years ago

Help please I NEED TO PASS :(((((

adoni [48]

Answer:

The answer should be C

Step-by-step explanation:

I just got done calculating it and according to my calculations it should be C

5 0

3 years ago

Anyone have the answer for this

sergiy2304 [10]

$\huge\bold{Given:}$

Length of the base = 16 km.

Length of the hypotenuse = 34 km. $\huge\bold{To\:find:}$

✎ The length of the missing leg '' $a$ ".

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

The length of the missing leg "a" is $\boxed{30\:km}$ .

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

Using Pythagoras theorem, we have

$({perpendicular})^{2} + ({base})^{2} = ({hypotenuse})^{2} \\ ⇢ {a}^{2} + ({16 \: km})^{2} = ({34 \: km})^{2} \\ ⇢ {a}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇢ {a}^{2} = 1156 \: {km}^{2} - 256 \: {km}^{2} \\ ⇢ {a}^{2} = 900 \: {km}^{2} \\ ⇢a \: = \sqrt{900 \: {km}^{2} } \\ ⇢a = \sqrt{30 \times 30 \: {km}^{2} } \\ ⇢a = 30 \: km$

$\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}$

$\huge\bold{To\:verify :}$

$( {30 \: km})^{2} + ({16 \: km})^{2} =( {34 \: km})^{2} \\ ⇝900 \: {km}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\⇝1156 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇝L.H.S.=R. H. S$