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lyudmila [28]
3 years ago
15

Billy anderson is choosing between two fitness centers. Center A charges $495 per year for unlimited use of all facilities. Cent

er B charges a $25 sign up fee, a $15 monthly fee, and $5 per aerobics class. If billy goes to aerobics once a week, which club is least expensive for him to use for a year
Mathematics
2 answers:
Darya [45]3 years ago
7 0

Let's compare the cost of both the centers.

<u>Cost of Center A:</u>

One time charge of $495 in one year.

<u>Cost of Center B:</u>

  • Flat $25 dollar sign up fee
  • $15 per month, so 15*12=180 dollars a year
  • $5 per aerobic class, so 5*52=260 dollars a year (given that Billy goes to class once a week) (<em>Note: There are 52 weeks in a year</em>)

Total cost = 25+180+260=465 dollars

Hence, Center B would cost 495-465=30 dollars cheaper.


ANSWER: Least expensive club for Billy to use for a year is Center B

Ahat [919]3 years ago
6 0
It would be cheaper for Billy Anderson to go to Center B because the 25 dollar sign up fee plus the 15 dollars a month for 12 months plus 5 dollars a week for 52 weeks is 25+180+260 is 465 so he would save $30 dollars
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<h2>Answer:</h2>

\frac{2}{x}

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In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

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b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

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