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Mazyrski [523]
3 years ago
14

Which statement is true? Plz someone help!

Mathematics
1 answer:
forsale [732]3 years ago
8 0
It should be II only. AED and ABC line up with each other bc of the marked angle
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Hello please help thanks
poizon [28]

Answer:

Sebment

Step-by-step explanation:

5 0
3 years ago
Kim picked 250 pounds of pears yesterday and 287 pounds of pears today. What is the percentage increase of
xxMikexx [17]

Given:

Kim picked 250 pounds of pears yesterday and 287 pounds of pears today.

To find:

The percentage increase of  amount of pears picked by Kim.

Solution:

We know that,

\%\text{ increase}=\dfrac{\text{New value - Initial value}}{\text{Initial value}}\times 100

\%\text{ increase}=\dfrac{287-250}{250}\times 100

\%\text{ increase}=\dfrac{37}{25}\times 10

\%\text{ increase}=\dfrac{370}{25}

\%\text{ increase}=14.8

Therefore, the percentage increase of  amount of pears picked by Kim is 14.8%.

7 0
3 years ago
A poll estimates that 47% of likely voters are in favor of additional restrictions on teenage drivers. The poll has a margin of
agasfer [191]

Answer:

5

Step-by-step explanation:

5 0
2 years ago
1.Find the area of a circle with the radius of 48mm
OLga [1]

Answer:

hope it helps you see the attachment for further information....

3 0
3 years ago
The volume V of a gas varies inversely as the pressure P and directly as the temperature A certain gas has a volume of 10 liters
Ad libitum [116K]

Answer:

Joint variation states that:

If z is directly proportional to x and inversely proportional to y,

i.e, z \propto x , z \propto \frac{1}{y}

then the equation is in the form: z = k\frac{x}{y} where k is the constant of variation.

From the given information: The volume V of a gas varies inversely as the pressure P and directly as the temperature

i.,e V \propto T , V \propto \frac{1}{P}

by definition of joint variation:

V = k\frac{T}{P}  .....[1] where k is the constant of variation.

It is also given that a certain gas has a volume of 10 liters(L) , a temperature of 300 kelvins(K), and a pressure of 1.5 atmosphere(atm).

Substitute these given values in [1] to solve for k;

10 = k\frac{300}{1.5}

Simplify:

10 = 200k

Divide by 200 both sides we have;

k = \frac{10}{200} =\frac{1}{20}

Now, if a gas has a temperature of 400 kelvins and a pressure of 5 atm.

To find the volume (V);

Now substitute the given data and value of k in [1] we have;

V = \frac{1}{20} \cdot \frac{400}{5} = \frac{20}{5} = 4

Therefore, the Volume of a gas is, 4 liters


5 0
3 years ago
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