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tatyana61 [14]
3 years ago
11

Write the equation in either slope-intercept or point-slope form for the

Mathematics
1 answer:
scZoUnD [109]3 years ago
6 0

Answer:

y = mx + b

m = (-5-1)/(3-1)

m = -3

1=(-3)1 + b

b= 4

y= -3x + 4

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Answer:

Step-by-step explanation:

it’s the last one

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What five key factors of a quadratic graph can be identified?
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The five key factors of a quadratic graph are:

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<h3>Meaning of a quadratic graph</h3>

A quadratic graph is a graph that is derived from a qudratic equation or function.

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2 years ago
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The wilsons have triplets and another child who is the twelve years old. The sum of the ages of their children is 39. How old ar
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The triplets are each 9 years old.

You can subtract 12 from 39 to get 27, then divide by 3 because of the three other kids
8 0
3 years ago
A Family purchased tickets to the movies in spent a total of $40.75. The family purchase five tickets there was a $.90 processi
muminat

Answer:

$7.25

Step-by-step explanation:

Total amount spent on the ticket   = $40.75

Number of ticket purchased  = 5

Processing fee per ticket  = $0.90

Unknown:

Cost of each ticket = ?

Solution:

To solve this problem, we need to find the processing fee for the 5 tickets purchase;

      Processing fee = number ticket x processing fee per ticket

      Processing fee  = 5 x 0.9  = $4.5

Now, the real cost a ticket = $40.75  - $4.5  = $36.25

So, cost per ticket is;

        Cost  = \frac{36.25}{5}   = $7.25

7 0
3 years ago
4. At a local university 54.3% of incoming first-year students have computers. If 3 students are selected at random, and the fol
valentinak56 [21]

Answer:

a) 0.0954

b) 0.9045

c) 0.1601

Step-by-step explanation:

We are given the following information:

We treat first-year students having computers as a success.

P(first-year students have computers) = 54.3% = 0.543

Then the number of first year students follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3

a) P(None have computers)

P(x =0) \\\\= \binom{3}{0}(0.543)^0(1-0.543)^3\\\\= 0.0954

b) P(At least one has a computer)

P(x \geq 1) \\\\= \binom{3}{0}(0.543)^0(1-0.543)^3+\binom{3}{1}(0.543)^1(1-0.543)^2+\binom{3}{3}(0.543)^3(1-0.543)^0\\\\=0.3402+0.4042+0.1601= 0.9045

c) P(All have computers)

P(x =3) \\\\= \binom{3}{3}(0.543)^3(1-0.543)^0\\\\= 0.1601

3 0
3 years ago
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