This can be solved by Newton's binomial formula
Tk+1 = (n k) a∧(n-k) b∧k k+1=7 => k=6, n=11 , a=-3x and b=-2y
T7= (11 6) (-3x)∧(11-6) (-2y)∧6 = (11*10*9*8*7)/(1*2*3*4*5) (-3x)∧5 (-2y)∧6
T7= 462 (-3x)∧5 (-2y)∧6
The correct answer is A.
Good luck!!!
9514 1404 393
Answer:
-1 < x < 2
Step-by-step explanation:
The graph indicates the variable may take on values between -1 and 2, not including those values. The compound inequality is written ...
-1 < x < 2
Step-by-step explanation:
We can prove that the triangles are congruent using the SAS method.
It's given that GH and JH are congruent (S)
Angle GHF and Angle IHJ are equal since they are vertically opposite (A)
It's given that FH and HI are congruent (S)
Thus, the triangles are congruent, which implies that the remaining sides are equal.
