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Lady_Fox [76]
3 years ago
14

PLEASE HELP SEE PICTURE!!!!!

Mathematics
1 answer:
oee [108]3 years ago
6 0
I think it’s a I hope I’m right
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Find the 89th term of the arithmetic sequence 25, 35, 45, ...
Eddi Din [679]

Answer:

905

Step-by-step explanation:

arithmetic sequence are in form

a(n)=a(0)+d(n-1)

a(0)=25

common difference: d=35-25=10

a(n)=25+10(n-1)

a(89)=25+10(88)=905

8 0
3 years ago
2(y + 5) = 18 - 12
Mrac [35]

Answer:

Distributive property

8 0
3 years ago
The table represents the number of cheese crackers in the lunchboxes of 9 boys and 9 girls. By looking at the table, does it app
Westkost [7]
CAN SOMEONE PLEASE ANSWER IT RIGHT NOW I NEED IT!!
5 0
3 years ago
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Mr. Cruz bought 9 3/5 kg of meat. He used 2 3/5 kg for adobo, 4 3/5 kg for menudo and the rest for afritada. How many kilograms
Ray Of Light [21]

Answer:

3 3/5

Step-by-step explanation:

5 0
3 years ago
The first five terms of a pattern are shown.
Andrej [43]

Answer:

C

Step-by-step explanation:

There is a common ratio between consecutive term in the sequence, that is

\frac{3}{10} ÷ \frac{3}{100} = 3 ÷ \frac{3}{10} = 30 ÷ 3 = 300 ÷ 30 = 10

This indicates the sequence is geometric with n th term

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Here a = \frac{3}{100} and r = 10 , thus

a_{n} = \frac{3}{100} (10)^{n-1}

    = \frac{3}{10^{2} } × 10^{n-1}

    = 3 × 10^{-2} × 10^{n-1}

    = 3 × 10^{n-3}

Thus

a_{n} = 3(10)^{n-3} → C

6 0
4 years ago
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