The answer is A, good luck
Answer:
80 MOLES OF WATER ARE PRODUCED WHEN 20 MOLES OF PROPANE ARE BURNED IN EXCESS OXYGEN ON A GAS GRILL.
Explanation:
Equation for the reaction:
C3H8 + 5 O2 ---------> 4 H2O + 3 CO2 + Heat
The above equation is in the presence of excess oxygen.
In this reaction,
1 mole of propane forms 4 moles of H2O
If 20 moles of propane were to be used, how many moles of water will be produced?
1 mole of propane = 4 moles of water
20 moles of propane = ( 4 * 20 ) moles of water
= 80 moles of water.
So, if 20 moles of propane were burned in excess oxygen, 80 moles of water will be formed. Propane is heavier than air and when properly combusted produces a large amount of heat. It is also non toxic.
It forms covalent compounds
Explanation is in a file
bit.
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Answer:
.259 g
Explanation:
PV = nRT
n = PV / RT
= .986 x 0.144 / .082 x 293.6
= .005897 moles
= .005897 x 44 g
= .259 g
