Put it in a beaker. Use a smaller beaker filled half way with ice and water and place in the larger one. It should be about an inch or two above the mixture. Heat over a Bunsen burner and the naphthalene will deposit on the bottom of smaller beaker.
And in this way, nephthalene be separated from the mixture of KBR and sand.
Answer:
![\large \boxed{\text{4.5 atm}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B4.5%20atm%7D%7D)
Explanation:
The volume and amount of gas are constant, so we can use Gay-Lussac’s Law:
At constant volume, the pressure exerted by a gas is directly proportional to its temperature.
![\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}](https://tex.z-dn.net/?f=%5Cdfrac%7Bp_%7B1%7D%7D%7BT_%7B1%7D%7D%20%3D%20%5Cdfrac%7Bp_%7B2%7D%7D%7BT_%7B2%7D%7D)
Data:
p₁ =5.7 atm; T₁ = 100.0 °C
p₂ = ?; T₂ = 20.0 °C
Calculations:
1. Convert the temperatures to kelvins
T₁ = (100.0 + 273.15) K = 373.15
T₂ = (20.0 + 273.15) K = 293.15
2. Calculate the new pressure
![\begin{array}{rcl}\dfrac{5.7}{373.15} & = & \dfrac{p_{2}}{293.15}\\\\0.0153 & = & \dfrac{p_{2}}{293.15}\\\\0.0153\times 293.15 &=&p_{2}\\p_{2} & = & \textbf{4.5 atm}\end{array}\\\text{The new pressure will be $\large \boxed{\textbf{4.5 atm}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5Cdfrac%7B5.7%7D%7B373.15%7D%20%26%20%3D%20%26%20%5Cdfrac%7Bp_%7B2%7D%7D%7B293.15%7D%5C%5C%5C%5C0.0153%20%26%20%3D%20%26%20%5Cdfrac%7Bp_%7B2%7D%7D%7B293.15%7D%5C%5C%5C%5C0.0153%5Ctimes%20293.15%20%26%3D%26p_%7B2%7D%5C%5Cp_%7B2%7D%20%26%20%3D%20%26%20%5Ctextbf%7B4.5%20atm%7D%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20new%20pressure%20will%20be%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B4.5%20atm%7D%7D%24%7D)
A technician mixes 80 ml of a 5% solution with 10 ml of water. the final percentage strength of the solution prepared is 40 %.
given that :
8 ml of a 5 % solution mix with 10 ml . that means the 80 mL of 5 % solution is diluted with water of 10 mL
therefore, 80 × 5 = 10 × x %
x % = 40 %
Therefore, the final percentage strength of the solution is 40 %
Thus, A technician mixes 80 ml of a 5% solution with 10 ml of water. the final percentage strength of the solution prepared is 40 %.
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Answer:
The pH of the solution is 4.60.
Explanation:
The pH gives us an idea of the acidity or basicity of a solution. More precisely, it indicates the concentration of H30 + ions present in said solution. The pH scale ranges from 0 to 14: from 0 to 7 corresponds to acid solutions, 7 neutral solutions and between 7 and 14 basic solutions. It is calculated as:
pH = -log (H30 +)
pH= -log (2,5 x 10-5)
<em>pH=4.60</em>
Answer:
HCl is the correct answer