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arlik [135]
3 years ago
12

Please help :') *picture attached !*

Chemistry
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

Pressure is 2.32 atm

Explanation:

Pressure . Volume = moles . Constant Ideal Gases . Temperature (K)

Pressure = (moles . Constant Ideal Gases . T° K) / Volume

T°K = T°C + 273 → 61°C + 273 = 334 K

Let's replace every data:

P = (0.214 mol . 0.082 L.atm/mol.K . 334K) / 2.53L

P = 2.32 atm

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The answer is Thermal Energy :)

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I don’t see anything
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A 30-kg girl and a 25-kg boy face each other on friction-free roller blades. the girl pushes the boy, who moves away at a speed
dsp73
0.83 m/s seems the correct answer, hope it helps
6 0
2 years ago
Pb(SO4)2 + 4 LiNO3 → Pb(NO3)4 + 2 Li2SO4
Anvisha [2.4K]

Answer:

4.5 moles of lithium sulfate are produced.

Explanation:

Given data:

Number of moles of lead sulfate = 2.25 mol

Number of moles of lithium nitrate = 9.62 mol

Number of moles of lithium sulfate = ?

Solution:

Chemical equation:

Pb(SO₄)₂ + 4LiNO₃      →     Pb(NO₃)₄ + 2Li₂SO₄

Now we will compare the moles of lithium sulfate with lead sulfate and lithium nitrate.

                       Pb(SO₄)₂        :         Li₂SO₄

                            1                :             2

                          2.25           :          2/1×2.25 = 4.5 mol

                       LiNO₃            :             Li₂SO₄

                           4                :                2

                           9.62           :             2/4×9.62 = 4.81 mol

Pb(SO₄)₂  produces less number of moles of Li₂SO₄ thus it will act as limiting reactant and limit the yield of  Li₂SO₄.      

7 0
2 years ago
You observe 2 waves named alpha and beta. The alpha wave has a frequency of 5 Hz and the beta wave has a frequency of 2 Hz. Base
MAVERICK [17]

Answer:

shorter wavelength = alpha wave

Explanation:

Given that,

The alpha wave has a frequency of 5 Hz and the beta wave has a frequency of 2 Hz.

We need to compare the wavelengths of these two waves.

For alpha wave,

\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{5}\\\\=6\times 10^7\ m

For beta wave,

\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{2}\\\\=15\times 10^7\ m

From the above calculations, we find that the wavelength of the alpha wave is shorter than the wavelength of the beta wave.

8 0
2 years ago
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