How many grams of CO2 will be produced when 8.50 g of methane react with 15.9 g of O2, according to the following reaction? CH4
1 answer:
The amount of that would be produced will be 10.93 g
From the equation of the reaction, the mole ratio of methane to oxygen is 1:2.
Mole of 8.50 g methane = 8.50/16.04 = 0.53 moles
Mole of 15.9 g oxygen = 15.9/32 = 0.4969 moles
Thus, methane is in excess while oxygen is limiting.
Mole ratio of and
= 2:1
Equivalent mole of = 0.4969/2 = 0.25 moles
Mass of 0.25 moles = 0.25 x 44.01 = 10.93 g
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log 0.53913 =
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Answer:
Average = 63.6
Explanation:
Average : The average of the given set of points can be calculated by dividing sum of the total point to the number of points.
The points that are given in this equation are:
83.2 , 44.6 , 74.4 , 52.3 .
These are 4 in number . So average is
Significant digits : It is the number of digits that carry meaningful value to a measurement. The rules for counting number of significant digits are:
1. all non-zero digit are significant
2.Any zero between two non-zero are also significant.(305 = 3 significant digit )
3. Zero before the decimal are non-significant (0.003 = only 1 significant digit)
Zero after decimal are significant (3.00 has 3 significant digit)
4.Zero after non - zero digit is non significant (300 has 1 significant digit).
Significant digits in division :
The answer should have the significant digits that are least in any of number(83.2 , 44.6 , 74.4 , 52.3 )
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Answer should have total = 3 significant digits
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Answer:
c. A and C have the same boiling point, but B has a lower one.
Explanation:
The freezing point depression is expressed as:
ΔT = kf×m
Where kf is the freezing point depression constant that depends the nature of the solvent and m is molality (mol of solute/kg of solvent)
Boiling point elevation is:
ΔT = kb×m
Where kb is the ebulloscopic constant of the solvent.
As kf, kb and mass of solvent is the same for A, B and C solutions the only difference will be in moles of solute.
<em>A </em>6,84g of sucrose are:
6,84g× = <em>0,002 moles</em>
<em>B </em>0,72g of ethanol are:
0,72g× = <em>0,0016 moles</em>
<em>C </em>0,40g of sodium hydroxide are:
0,40g× = <em>0,001 moles</em>
Using Van't Hoff factor that describes the number of moles in solution that comes from 1 mole of solute before dissolving, moles in solution for A, B and C are:
A. moles in solution: 0,02 moles×1 = <em>0,02 moles in solution</em>
B. moles in solution: 0,016 moles×1 = <em>0,016 moles in solution</em>
C. moles in solution: 0,01 moles×2 = <em>0,02 moles in solution</em>
As A has the same moles in solution of C, the freezing point depression will be the same in A and C, and the lower freezing point depression will be in B.
Also, the boiling point will be higher in A and C, and then in B.
Thus:
a. C has the lowest freezing point in the group. <em>FALSE. </em>A and C have the lowest feezing point because have the higher freezing point depression.
b. A, B, and C all have different freezing points. <em>FALSE. </em>As moles of A and C are the same, freezing point will be the same for the solutions.
c. A and C have the same boiling point, but B has a lower one. <em>TRUE. </em>
d. The boiling point of C is lower than that of A or B . <em>FALSE. </em>Boiling point of C and A is higher than B.
e. A, B, and C will all have about the same freezing points. <em>FALSE</em>