Answer: A 59.5 degree celcius
The equation that we will use to solve this problem is :
PV = nRT where:
P is the pressure of gas = 1.8 atm
V is the volume of gas = 18.2 liters
n is the number of moles of gas = 1.2 moles
R is the gas constant = 0.0821
T is the temperature required (calculated in kelvin)
Using these values to substitute in the equation, we find that:
(1.8)(18.2) = (1.2)(0.0821)(T)
T = 332.5 degree kelvin
The last step is to convert the degree kelvin into degree celcius:
T = 332.5 - 273 = 59.5 degree celcius
Answer:
Test for an odor. The nonpolar substance should have a higher volatility and stronger odor because of its London dispersion forces.
Explanation:
To help Ming identify the non-polar compound, assuming the non-polar compound will have an odor test for it and most importantly, the non-polar substance should have a higher volatility due to its London dispersion forces.
- London dispersion forces are weak attractions found between non-polar molecules and noble gases.
- They account for the reason why compounds as such are volatile
Answer:
1.2 moles
Explanation:
this is the balanced equation for the reaction of oxygen (O2) and hydrogen (H2), usually we don't write the 1 in front of O2
2H₂ + 10₂ → 2H₂O
the molar ratio of hydrogen to oxygen is 2 : 1
we are trying to react with 2.4 mol of H2 so the moles of O2 is half the number of moles of H2 = 2.4 ÷ 2 = 1.2 mol
another way to think of it:
2H₂ + 10₂
2 : 1
2.4 mol : x mol
to get from 2 to 2.4 multiply by 1.2, so do the same to the other side
1 × 1.2 = 1.2 mol
