the domain is the x value (first number) and the range is the y value (second number)
(if a number appears more than once in the domain or range, like in number 1 you don't have to write it again.)
to graph the domain and range you just plot the points,
and to map them you have to put the x values in the first oval and the y values in the second, usually in order from smallest to largest.
then you have to draw arrows connecting each x value to the y value that was in the same pair. just like when writing down the domain/range, if a number comes up again you don't have to write it down again. instead, you might have two or more arrows connecting to the same number.
Answer:
a) the radius of the balloon increases at a rate of 5.42 in/s
b) the surface area of the balloon increases at a rate of 3 in²/s
Step-by-step explanation:
a) since the volume of a sphere V is
V= 4/3*π*R³
where R= radius , then the rate of change of the volume is
V' = dV/dR= 4*π*R²
using the chain rule
dV/dt = dV/dR*dR/dt
thus
k = 4*π*R² * dR/dt
dR/dt = k/(4*π*R²)
replacing values
dR/dt = k/(4*π*R²) = (33 in³/s) /(4*π*(22 in)²] = 5.42 in/s
then the radius of the balloon increases at a rate of 5.42 in/s
b) since the surface area is
S=4*π*R²
then
S' = dS/dR= 8*π*R
and
dS/dt = dS/dR*dR/dt = 8*π*R * k/(4*π*R²) = 2*k/R
replacing values
dS/dt = 2*k/R = 2*(33 in³/s)/( 22 in) = 3 in²/s
then the surface area of the balloon increases at a rate of 3 in²/s
Answer:
The answer is (-3X+6i)(x+2i)
Step-by-step explanation:
You can do this by plugging in the answers in the equations and get that (-3x+6i)(x+2i) equals the following expression.
