We have by the intermediate value theorem that if a continuous function takes values both above and below zero at 2 points, there is a zero of the function in-between. We have that polynomials are continues. Let's calculate f(-6) and f(-5). f(-6)=-36 while f(-5)=-1. Thus, we cannot conclude that there is a root between them.
F(-2)=8, f(-1)=-1, so there is a flip; a zero must exist between them.
F(1)=-1, f(2)=20, so again there is a change of signs.
f(-5)=-1, f(-4)=14 so there is a root still.
We have that the only choice that does not have a root between the integers is choice a.
First, lets take all the x values on one side.
3x + x + 8 = -x + x + 20
4x + 8 = 20
Now, lets put the numbers on the other side.
4x + 8 - 8 = 20 - 8
4x = 12
x = 3
Hope this helps!
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Answer:
The answer to your question is x ² + y² = 64
Step-by-step explanation:
Process
1.- Find the length of the radius
C (0, 0)
P (0, -8)
d = 
d = 
d = 
d = 8
2.- Find the equation of the circle
h = 0 and k = 0
x² + y² = 64
Answer:
10
Step-by-step explanation:
<em>10 + 10 = 2x</em>
<em>2x = 20</em>
<em>10 + 10 = 20</em>
<em>x = 10</em>
have a nice day and mark me brainliest! :)
The answer would be -4 because if you do -4 times 2x then you would get -8x. Then if you did -4 times -3 you would get 12. (A negative times a negative equals a positive)
