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2 years ago

Which of the following expressions are equivalent to −5.93+(−8.62)+5.93?

Mathematics

2 answers:

vampirchik [111]2 years ago

7 0

Answer:

A, B, C, D

Step-by-step explanation:

−5.93 + (−8.62) + 5.93 =
−5.93 - (8.62 - 5.93) = B
−(5.93 + 8.62) + 5.93 = C
−5.93 −8.62 - (- 5.93) = D
-8.62 A

Tems11 [23]2 years ago

4 0

ANSWER:

[a] – 8.62

[b] – 5.93 –(8.62 – 5.93)

– 5.93 – 8.62 + 5.93
– 8.62

[c] –(5.93 + 8.62) + 5.93

– 5.93 – 8.62 + 5.93
– 8.62

[d] – 5.93 – 8.62 –(–5.93)

– 5.93 – 8.62 + 5.93
– 8.62

[e] – 5.93 –(8.62 + 5.93)

– 5.93 – 8.62 – 5.93
– 8.62 – 11.86
– 20.48

So, <u>Correct choice</u> - [a] ; [b] ; [c] ; [d].

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Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

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3 years ago

Simplify the following rational expression and express in expanded form.

VladimirAG [237]

Answer:

D m = $-\frac{3}{8}$

Step-by-step explanation:

factor the expressions in the denominator and the numerator to simplify the expression:

=> $\frac{2(-2m + 1)(2m - 1)}{2(2m - 1)(8m + 3)}$

=> $-\frac{2m + 1}{8m + 3}$

to make a fraction undefined, the numerator should be 0, thus, we substitute the values of m from the options into the denominator to make the denominator equals to 0:

=> $-\frac{2m + 1}{8(-\frac{3}{8} ) + 3}$ = $-\frac{2m + 1}{-3 + 3}$ = $-\frac{2m + 1}{0}$