Please solve and explain the question below
1 answer:
Answer:
OPTION A
Step-by-step explanation:
To find the table substitute the points on the given function and compare the values.
The given function is: .
OPTION A:
(i) When x = -2
LHS = y = 6.
RHS = (-2)² + 2 = 4 + 2 = 6.
LHS = RHS
(ii) When x = -1
LHS = y = 3
RHS = (-1)² + 2 = 1 + 2 = 3.
LHS = RHS
(iii) When x = 0
LHS = y = 2
RHS = 0² + 2 = 2.
LHS = RHS
(iv) When x = 1
LHS = y = 3
RHS = (1)² + 2 = 1 + 2 = 3.
LHS = RHS
(v) When x = 2
LHS = y = 6
RHS = (2)² + 2 = 4 + 2 = 6
LHS = RHS
OPTION B:
(i) When x = -2
LHS = y = -2
RHS = (-2)² + 2 = 6
LHS RHS
OPTION B is eliminated.
OPTION C:
(i) When x = -2
Using the same reason as OPTION B this option is eliminated as well.
So, OPTION A is the correct answer.
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Answer:
Probability that a battery is both made by Factory A and defective is 0.012 or 1.2%.
Step-by-step explanation:
We are given that Two factories — Factory A and Factory B — design batteries to be used in mobile phones. Factory A produces 60% of all batteries, and Factory B produces the other 40%.
2% of Factory A's batteries have defects, and 4% of Factory B's batteries have defects.
Let the Probability that factory A produces batteries = P(A) = 0.60
Probability that factory B produces batteries = P(B) = 0.40
<em>Also, let D = event that battery is defective</em>
Probability that batteries have defects given that it is produced by Factory A = P(D/A) = 0.02
Probability that batteries have defects given that it is produced by Factory B = P(D/B) = 0.04
Now, <u>probability that a battery is both made by Factory A and defective</u> = Probability that factory A produces batteries Probability that batteries have defects given that it is produced by Factory A
= P(A) P(D/A)
= 0.60 0.02 = 0.012 or 1.2%
Therefore, the probability that a battery is both made by Factory A and defective is 1.2%.