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timurjin [86]
3 years ago
5

The sum of three numbers of an AP is 12 and the sum of their cubes is 288 find the numbers.

Mathematics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

The numbers are 2 , 4 , 6 or 6 , 4 , 2

Step-by-step explanation:

For solution kindly refer to the attachment .

<u>Related</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u><u> </u>

• The sum of n terms of an AP is ,

=> S = n/2 [ 2a + ( n - 1 ) d ]

• The nth term of an AP is ,

=> T_n = a + ( n - 1 ) d

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Can I get some help with this question plzzz
victus00 [196]
All the possible combinations are
1-1 2-1 3-1 4-1 5-1 6-1
1-2. 2-2 3-2 4-2. 5-2. 6-2
1-3 2-3. 3-3. 4-3. 5-3. 6-3
1-4. 2-4. 3-4. 4-4. 5-4. 6-4
1-5. 2-5. 3-5. 4-5. 5-5. 6-5
1-6. 2-6. 3-6. 4-6. 5-6. 6-6

What is the total for each roll?

2. 3. 4. 5. 6. 7.
3. 4. 5. 6. 7. 8
4. 5. 6. 7. 8. 9
5. 6. 7. 8. 9. 10.
6. 7. 8. 9. 10. 11.
7. 8. 9. 10. 11. 12

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7 occurs in 6 out of 36 possible outcomes
7 0
3 years ago
Suppose that F is an inverse square force field below, where c is a constant.
Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

a)

First of all we have,

F(r) = \frac{cr}{|r|^{3} }

and,

r = xi+yj+zk

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

f(r) = - c /|r|

That is,

\nabla f = F

For this case F is a conservative field and the line integral is independent of the path. Thus, defining  P_{1} = (x_{1}, y_{1}, z_{1}) and P_{2} = (x_{2}, y_{2}, z_{2}) . So the amount of work on the movement of the object from P1 to P2 is,

W=\int\limits_c  {F} \, dr

W= f(P_{1}-P_{2})

W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}

W= c(\frac{1}{d1}-\frac{1}{d2}  )

2) The gravitational force field is given by,

F(r) =-\frac{mMGr}{ |r|^3}

The maximum distance from the earth to the sun is 1.52*10 ^ 8 km and the minimum distance is 1.47*10 ^ 8km. The mass values of the bodies are given by m = 5.97*10 ^ {24}kg, M = 1.99 *19 ^ {30}kg and the constant G is 6.67 * 10 ^{ -11 } \frac{Nm ^ 2}{kg^2}

In this way we raise the problem like this,

c= -mMG

W= -mMG (\frac{1}{1.52*10 ^ 8} -\frac{1}{1.47*10 ^ 8} )

W= -(5.95*10^{24})(1.99*10^{30})(6.67*10^{-11})(-2.2377*10^{-10})

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5 0
2 years ago
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sergejj [24]
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3 0
3 years ago
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If u is a unit vector, find u · v and u · w. (assume v and w are also unit vectors.) equilateral triangle
serg [7]

solution:

we know that ,

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here,

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u.v = ΙuΙ ΙvΙcos60°

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u.v = 1/2

now, u.w = ΙuΙ ΙwΙcosθ

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Nady [450]

Answer: the answer is 7

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8 0
3 years ago
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