Divide both sides by the numeric factor on the left side then solve x=9
HG^2 = FG * (FG + EF)
Fill in the values:
(x+3)^2 = x * (7+x)
Simplify the right side:
(x+3)^2 = 7x +x^2
Rewrite the left side using the FOIL method
x^2 + 6x + 9 = 7x +x^2
Subtract x^2 from both sides:
6x +9 = 7x
Subtract 6x from both sides:
x = 9
Now you have x solve for HG
HG = x +3 = 9+3 = 12
The answer is A.
Remember
x^-m=1/(x^m)
u^-3=1/(u^3)
1/(u^3)=1/125
therefor
u^3=125
u=5
x=-3
easy
y=-3-13
y=-16
correct
normally, y is output
(x,y)
chose al second numbers
0,3 are all acceptable
B and D
y=mx+b
m=-3
y=-3x+b
sub point
(x,y)
(1,-2)
-2=-3(1)+b
-2=-3+b
1=b
y=-3x+1
remember (x,y) you keep swtiching those
