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barxatty [35]
3 years ago
15

Could anyone please help me with this? I don't get this​

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

23

Step-by-step explanation:

the angles are equal to each other so we use the equation

6x-7=9x-22 and solve for x

step 1 subtract 6 from each side

-7=3x-22

step 2 add 22 to each side

3x=15

step 3 divide each side by 3

x=5

then to find the angle abd we plug in 5 to 9x-22

9x5=45

45-22=23 so angle abd=23

hope this helps (:

if you have any more questions feel free to ask

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13 please I have no idea what the steps for this is
Ilya [14]

Answer:

UV=142

Step-by-step explanation:

21x-13=10x+31

+13 +13

21x=10x+44

-10x=-10x

11x=44

÷11 ÷11

x=4

now substitute 4 in place of x (only have to solve one)

21(4)-13= 71

now multiply your answer by 2

71×2=142

6 0
4 years ago
Find the missing side of this right triangle.
Alborosie

Answer:

13

Step-by-step explanation:

it's a 5,12,13 triangle

and we can find the sides by Pythagorean theorem:

a^2 + b^2 = root of c

25 + 144 = 169

root of 169 = 13

3 0
3 years ago
Simplify:0.3(x-2y)+0.5x-y
astraxan [27]

Answer:

0.3[x-2y] + 0.5x - y


Use the distributive property: a(b-c) = ab - ac


0.3x - 0.6y + 0.5x - y


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0.3x + 0.5x - 0.6y - y


0.8x - 1.6y


If you want, we can simplify that down further to:


0.8(x - 2y)



7 0
4 years ago
Read 2 more answers
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir
Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

\sigma = \sqrt{484} = 22

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

M = z*\frac{\sigma}{\sqrt{n}}

5 = 1.96*\frac{22}{\sqrt{n}}

5\sqrt{n} = 43.12

\sqrt{n} = \frac{43.12}{5}

\sqrt{n} = 8.624

(\sqrt{n})^{2} = (8.624)^{2}

n = 74.4

We need a sample size of at least 75.

6 0
4 years ago
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Lesechka [4]
8 of them are not blue
6 0
3 years ago
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