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Ivan
2 years ago
9

What is the wavelength of these waves?

Chemistry
1 answer:
Pepsi [2]2 years ago
3 0
It measure the distance between two consecutive waves within the phase.
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Do oxygen atoms become more stable or less stable when oxygen forms compounds? Explain
4vir4ik [10]
They become more stable because they achieve a full outer shell of valence electrons with the magic number of 8.

5 0
2 years ago
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if electrons in an atom have the lowest possible energies the atom is in the ground state true or false
nata0808 [166]
I believe the answer is true. Hope this helps.
7 0
3 years ago
The crack shown in the lithosphere was created by the movement of two or more tectonic plates. What is this crack called
nikitadnepr [17]

Answer:

The lithosphere is made up of pieces of tectonic plates. These plates are constantly changing and move towards the mantle. Non-stop movement of tectonic plates causes stress on the earth's outermost layer i.e,the crust. When these stresses extends it leads to cause cracks called faults.

Explanation:

4 0
2 years ago
The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.
user100 [1]

Answer:

c    43.38 g

Explanation:

The reaction  between MnO2 and HCl can be represented by the following balanced equation:

MnO2 + HCl ---> Cl2 + MnCl2 + H2O

From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.  

For the fact that HCl  gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess,  while the limiting reagent should be MnO2 .  

Thus, the theoretical yield of Cl2 will be  60.25 g.

By definition, the percentage yield is given by

% Yield = (Actual Yield) / (Theoretical Yield),  

This can be simplified to

Actual Yield = % Yield * Theoretical Yield

Plugging in the given values we have

Actual Yield = 72% *  60.25 = 43.38 g

5 0
3 years ago
5 moles of an ideal gas (Cp = 3R, Cv 2R ) are heated from 25°C to 300°C. Calculate (a) The change in internal energy of the gas
Artist 52 [7]

Answer :

(a) The change in internal energy of the gas is 22.86 kJ.

(b) The change in enthalpy of the gas is 34.29 kJ.

Explanation :

(a) The formula used for change in internal energy of the gas is:

\Delta U=nC_v\Delta T\\\\\Delta U=nC_v(T_2-T_1)

where,

\Delta U = change in internal energy = ?

n = number of moles of gas = 5 moles

C_v = heat capacity at constant volume = 2R

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 25^oC=273+25=298K

T_2 = final temperature = 300^oC=273+300=573K

Now put all the given values in the above formula, we get:

\Delta U=nC_v(T_2-T_1)

\Delta U=(5moles)\times (2R)\times (573-298)

\Delta U=(5moles)\times 2(8.314J/mole.K)\times (573-298)

\Delta U=22863.5J=22.86kJ

The change in internal energy of the gas is 22.86 kJ.

(b) The formula used for change in enthalpy of the gas is:

\Delta H=nC_p\Delta T\\\\\Delta H=nC_p(T_2-T_1)

where,

\Delta H = change in enthalpy = ?

n = number of moles of gas = 5 moles

C_p = heat capacity at constant pressure = 3R

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 25^oC=273+25=298K

T_2 = final temperature = 300^oC=273+300=573K

Now put all the given values in the above formula, we get:

\Delta H=nC_p(T_2-T_1)

\Delta H=(5moles)\times (3R)\times (573-298)

\Delta H=(5moles)\times 3(8.314J/mole.K)\times (573-298)

\Delta H=34295.25J=34.29kJ

The change in enthalpy of the gas is 34.29 kJ.

4 0
3 years ago
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