Balance the equation: 2Mg + O2 = 2(MgO) (Help!)

Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, the reaction is balanced. Now, the problem give to us two amounts of reagents. Therefore, we have to find the limiting reagent. The first step then is to find the moles of each compound using the molar mass:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can divide by the coefficient of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our limiting reagent. Now, if we use the molar ratio between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the molar mass of XY would be 85+24 = 109 g/mol. With this in mind:

$0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY$

I hope it helps!

6 0

3 years ago

compare the boiling point of water at sea leavel to the boiling point in denver (altitude = 1 mile) Explain

steposvetlana [31]

Answer:

boiling point decreases in denver

Explanation:

in higher places

theres less atmospheric pressure

it takes less energy to bring water to the boiling point.

Less energy means less heat

which means water will boil at a lower temperature

wonderopolisorg

6 0

2 years ago

A 1.26 m aqueous solution of an ionic compound with the formula mx2 has a boiling point of 101.63 ∘c. part a calculate the van't

12345 [234]

Answer is: Van't Hoff factor (i) for this solution is 1.051 .
Change in boiling point from pure solvent to solution: ΔT =i · Kb · b.
Kb - molal boiling point elevation constant is 0.512°C/m.
b - molality, moles of solute per kilogram of solvent.
b = 1.26 m.
ΔT = 101.63°C - 100°C = 1.63°C.

i = 1.63°C ÷ (0.512°C/m · 1.26 m).

i = 1.051.

5 0

3 years ago

Read 2 more answers

If a balloon is filled with a mixture of helium and oxygen, which gas will escape faster? Why?

Serjik [45]

Answer:

The rate of leakage will be higher for helium; its molecules move about 3 times faster than oxygen’s

Explanation:

Step 1: Data given

Molar mass helium = 4.0 g/mol

Molar mass O2 = 32 g/mol

Step 2: Graham's law

Graham's Law of Effusion states that the rate of effusion of a gas is inversely proportional to the square root of the molecular mass : 1/(Mr)^0.5

Rate of escape for He = 1/(4.0)^0.5 = 0.5

Rate of escape for O2 = 1/(32)^0.5 = 0.177

The rate of leakage will be higher for helium; its molecules move about 3 times faster than oxygen’s

4 0

3 years ago

In which of these would a nonpolar covalent bond be present? HBr H2O HCI Br2

cluponka [151]

Br2 is the correct answer

5 0

3 years ago