Your team has been hired to advice a fictional
agribusiness company named "Merced Grapes
and Wine", or MGW. MGW is located in the
Merced county, California, where the economy is
driven by agriculture, and works with many grape
farmers of the Central Valley providing different
services such as logistics and distribution,
product processing, and commercialization.
MGW has an annual revenue of $35,000,000
thanks to producing and selling 10,000,000 L of
wine and 25,000 tons of table grapes per year.
They spend per year $12,000,000 in logistics,
$8,000,000 in salaries for their approximately
100 employees, $4,750,000 in maintenance
(excluded electricity), $100,000 in electricity,
and $1,000,000 in other costs. The company
wants to renew itself, and you have been called
to help MGW adapting to new opportunities to
save money or to increase their profit. They have
some "raw ideas" of what to do with their waste,
and you must analyze them and advice which
ones, if any, are feasible. Background Wine waste
consists of grape seeds, skins, pulp residue, and
stems that are byproducts in wine production,
generated after applying low pressure to the
grapes to obtain higher quality must. By applying
higher pressure to them, some bitter substances
and other compounds are released, and the
quality of that wine is too low to be
commercialized. This residue is called pomace or
orujo (in Spanish), and it is currently disposed in
a landfill at a cost. - Waste production: 10,000
tons of wine residue per year. - Current use:
disposed at a landfill at a cost of $100/ton
(including all costs involved).
I need help with option 3 shown below:
Option #3. Extraction of bioactive compounds
(such as anthocyanins and other phenolic
Answer:
Technology improves a scientist's ability to make observations.
Explanation:
Answer:
yes brainly will give you the right answers
Explanation:
The balanced chemical reaction is:
<span>2SO2 + O2=2SO3
</span>
We are given the amounts of the reactants to be consumed in the reaction. These amounts are the starting point for the calculations.
5.0 L SO2 ( 1 mol / 22.4 L ) = 0.2232 mol SO2
3.0 L O2 <span> ( 1 mol / 22.4 L ) = 0.1339 mol O2
From the chemical reaction, the mole ratio of the reactants 2:1. Therefore, the limiting reactant is SO2.
</span><span>0.2232 mol SO2 ( 1 mol SO3 / 2 mol SO2) ( 22.4 L / 1 mol ) = 2.4998 L SO3</span>
