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Zarrin [17]
1 year ago
9

How do you convert volume to moles at STP?

Chemistry
1 answer:
Vanyuwa [196]1 year ago
6 0

The conversion of volume to moles at STP is 1 mole.

The ideal gas equation is given as :

P V = n R T

where,

P = pressure of the gas

V = volume of the gas

n = ?

R = constant = 0.823 atm L / mol K

T = temperature

At STP , the pressure is 1 atm and the temperature is 273.15 K, the volume At STP is 22.4 L.

moles , n = P V / R T

n = ( 1 × 22.4 ) / (0.0823 × 273.15)

n = 1 mole

Thus, at STP , the number of moles is 1 mol.

To learn more about moles here

brainly.com/question/8429153

#SPJ4

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The molar absorptivity for aqueous solutions of phenol at 211 nm is 6.17x103L/mol/cm. Calculate the linear range of phenol conce
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Explanation:

The given data is as follows.

          \lambda = 211 nm,          \sum = 6.17 \times 10^{3} mol/L/cm

           l = 1 cm,             7% < Transmittance < 85%

Suppose the aqueous solution follows Lambert-Beer's law. Therefore,

                   Absorbance = -log \frac{\text{Percentage transmittance}}{100}

Hence, for 7% transmittance the value of absorbance will be as follows.

                  Absorbance = -log \frac{7}{100}

                           A_{1} = 1.155

For 85% transmittance the value of absorbance will be as follows.

                 Absorbance = -log \frac{85}{100}

                           A_{2} = 0.07058

According to Lambert-Beer's law.

                  A = \sum \times l \times C

where,       A = absorbance

                 \sum = molar extinction coefficient

                 C = concentration

Therefore, concentration for 7% absorbance is as follows.

                    A_{1} = \sum \times l \times C_{1}

                  C_{1} = \frac{1.155}{6.17 \times 10^{3} \times 1}

                                  = 0.187 \times 10^{-3} mol/L

                                  = 0.187 mmol/L

Concentration for 85% absorbance is as follows.

                   A_{2} = \sum \times l \times C_{2}

                  C_{2} = \frac{0.07058}{6.17 \times 10^{3} \times 1}

                                  = 0.01144 \times 10^{-3} mol/L

                                  = 0.01144 mmol/L

Thus, we can conclude that linear range of phenol concentration is 0.01144 mmol/L to 0.187 mmol/L.

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