The answer to this question would be the last choice (this data has no outliers)
Explanation: The reason for this is that an outlier is basically any number or value that kind of stands off or is very separated from a set of data.
For example, if I had the numbers 1,2,3,2,9,5,7,5,8,4 and 47, 47 would definitely be an outlier as it's significantly greater than the rest of the data.
The data shown in your question doesn't vary a lot though, (it's contained within a range of 65 and 80- no number seems to be radically different).
Answer:
<em>g(</em><em>x)</em><em> </em><em>=</em><em> </em><em>-4g(</em><em>x)</em><em> </em><em>=</em><em> </em><em>-x+</em><em>4</em>
<em>=</em><em> </em><em>g(</em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em>4</em><em>(</em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em>(</em><em>5</em><em>)</em><em>+</em><em>4</em>
<em>=</em><em> </em><em>g(</em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em>
Answer:
The worth of the car after 6 years is £2,134.82
Step-by-step explanation:
The amount at which Dan buys the car, PV = £2200
The rate at which the car depreciates, r = -0.5%
The car's worth, 'FV', in 6 years is given as follows;
Where;
r = The depreciation rate (negative) = -0.5%
FV = The future value of the asset
PV = The present value pf the asset = £2200
n = The number of years (depreciating) = 6
By plugging in the values, we get;
The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))
=5 + 3 + 3 * 15
do multiplication first
=5 + 3 + 45
=8 + 45
=53
ANSWER: 53
Hope this helps! :)
