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3 years ago

I need this immediately!! Put the equation in standard form with a positive X coefficient. Y + 6 = 3/2 ( x - 4 ) HELP!!

Mathematics

2 answers:

inn [45]3 years ago

4 0

Answer:

3/2x -y = 12

Step-by-step explanation:

Y + 6 = 3/2 ( x - 4 )

Distribute the 3/2

y+6 = 3/2x - 12/2

y+6 = 3/2x -6

Subtract 6 from each side

y+6-6 = 3/2x -6-6

y = 3/2x -12

Subtract 3/2x from each side

-3/2x +y = 3/2x-3/2x -12

-3/2x +y = -12

We want a positive x so multiply by -1

-1(-3/2x +y) = -1* -12

3/2x -y = 12

Readme [11.4K]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

given

y + 6 = $\frac{3}{2}$ (x - 4)

Multiply through by 2 to eliminate the fraction

2y + 12 = 3(x - 4) ← distribute

2y + 12 = 3x - 12 ( subtract 2y from both sides )

12 = 3x - 2y - 12 ( add 12 to both sides )

24 = 3x - 2y, that is

3x - 2y = 24 ← in standard form

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What is the value of 12x^-3 y-1 for x=-1 and y=5<br> A.-12/5<br> B.-180<br> C.-60<br> D.-5/12

Mkey [24]

Expressions are mathematical statements represented with the variables

The value of 12x^-3 y-1 for x=-1 and y=5 is - 12/5

<h3>How to determine the value of the variable</h3>

The expression is given as:

$12x^{-3} y^{-1}$

When x = -1, the expression becomes

$12 * -1^{-3} y^{-1}$

Evaluate the exponent

$- 12 y^{-1}$

When y = 5, the expression becomes

$- 12 * 5^{-1}$

Evaluate the exponent

- 12/5

Hence, the value of 12x^-3 y-1 for x=-1 and y=5 is - 12/5

I need this immediately!! Put the equation in standard form with a positive X coefficient. Y + 6 = 3/2 ( x - 4 ) HELP!! ​

I need this immediately!! Put the equation in standard form with a positive X coefficient. Y + 6 = 3/2 ( x - 4 ) HELP!!