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jeyben [28]
3 years ago
10

Write the quadratic equation whose roots are 5 and 6 and whose leading coefficient is 5

Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0

9514 1404 393

Answer:

  5x^2 -55x +150 = 0

Step-by-step explanation:

A root of p means (x-p) is a factor. So, the factored form of the equation you want is ...

  5(x -5)(x -6) = 0

  5(x^2 -11x +30) = 0 . . . . . multiplying binomials

  5x^2 -55x +150 = 0 . . . . applying the leading coefficient

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Given that the function is f(x)=x^{3}-6 x^{2}+4 x+7

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Substituting x = 0 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(0)=(0)^{3}-6 (0)^{2}+4 (0)+7

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Substituting x = 5 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

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Thus, we have;

Rate \ of \ change=\frac{f(5)-f(0)}{5-0}

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Hello Love!! ♡ 

»»————-  \red{Answer\:} ————-««

\Huge{\boxed{\frac{1}{4}}}

☆♬○♩●♪✧♩ \bold{EXPLANATION\;} ♩✧♪●♩○♬☆

\mathfrak{apply~the~fraction~rule~:}~\frac{a}{c}~ -~\frac{b}{c} = \frac{a~-~b}{c}

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