Please help me solve this.

Mathematics

1 answer:

erastovalidia [21]3 years ago

8 0

Answer:

B. Subtract 7

Step-by-step explanation:

You always want to isolate the x term to solve for x in any equation. Therefore, we need to move the 7 to the other side. Only way to do that is to subtract 7 on both sides.

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Jake, Sara, and Cole are selling tickets for the school drama show. Sara sells half as many tickets as Jake. Cole sells 6 more t

3241004551 [841]

We let x be the number of tickets that Sara and Jake sold individually. With this representation, the number of tickets sold by Cole is equal to 2x+6.

(a) x + x + (2x + 6) = 538
The value of x from the generated equation is 133.

(b) Sara sold a total of 133 tickets.

7 0

3 years ago

Read 2 more answers

HELp meh with this question it very hard

Dovator [93]

Answer:

AB = 7 cm

Step-by-step explanation:

Use the law of cosines to find the side AB:

$AB = \sqrt{(x + 3)^2+x^2-2x(x+3)cos (60)} =$
$\sqrt{x^2+6x+9+x^2-x^2-3x} = \sqrt{x^2+3x+9}$

Use the Heron's area formula next:

$A = \sqrt{s(s - a)(s-b)(s-c)}$ , where s- semi perimeter

s = 1/2[x + x + 3 + $\sqrt{x^2+3x+9}$ ) = 1/2 (2x + 3 + $\sqrt{x^2+3x+9}$ )
s - a = 1/2 (2x + 3 + $\sqrt{x^2+3x+9}$ - 2x - 6) = 1/2 ( $\sqrt{x^2+3x+9 }$ - 3)
s - b = 1/2 (2x + 3 + $\sqrt{x^2+3x+9}$ - 2x) = 1/2 ( $\sqrt{x^2+3x+9}$ + 3)
s - c = 1/2 (2x + 3 + $\sqrt{x^2+3x+9}$ - 2 $\sqrt{x^2+3x+9}$ ) = 1/2 (2x + 3 - $\sqrt{x^2+3x+9}$ )