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3 years ago

Formula of atom bomb

Chemistry

1 answer:

Gnoma [55]3 years ago

5 0

Answer:

It says that the energy (E) in a system (an atom, a person, the solar system) is equal to its total mass (m) multiplied by the square of the speed of light (c, equal to 186,000 miles per second).

Explanation:

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3 years ago

For the following Bronsted acid-base reaction, complete the reaction, identify the acid, base, conjugate

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Answer:

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3 years ago

Balance the following chemical equation. CCl4 -> ___ C+ ___ Cl2

Bingel [31]

Answer:

Explanation:

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3 years ago

What accounts for the majority of all air pollution? Is that source increasing or decreasing overall?

lianna [129]

Hi there!

One of the main causes of air pollution is smoking.

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3 years ago

Read 2 more answers

Antimony has two naturally occuring isotopes, 121 Sb and 123 Sb . 121 Sb has an atomic mass of 120.9038 u , and 123 Sb has an at

valina [46]

Answer:

Percentage abundance of 121 Sb is = 57.2 %

Percentage abundance of 123 Sb is = 42.8 %

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 121 Sb :

% = x %

Mass = 120.9038 u

For second isotope, 123 Sb:

% = 100 - x

Mass = 122.9042 u

Given, Average Mass = 121.7601 u

Thus,

$121.7601=\frac{x}{100}\times 120.9038+\frac{100-x}{100}\times 122.9042$

$120.9038x+122.9042\left(100-x\right)=12176.01$

Solving for x, we get that:

x = 57.2 %

Thus, percentage abundance of 121 Sb is = 57.2 %

percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %

6 0

3 years ago

Formula of atom bomb​

Formula of atom bomb