Answer: 596 atm
Explanation:
Given that,
Original pressure of balloon P1 = 3atm
Original temperature of balloon T1 = 298K
New pressure of balloon P2 = 6atm
New temperature of balloon T2 = ?
Since pressure and temperature are given while volume is constant, apply the formula for Pressure law
P1/T1 = P2/T2
3 atm / 298K = 6 atm / T2
To get the value of T2, cross multiply
3 atm x T2 = 6 atm x 298K
3 atmT2 = 1788 atmK
Divide both sides by 3 atm
3 atmT2 / 3 atm = 1788 atmK / 3 atm
T2 = 596 atm
Thus, a temperature of 596 atmospheres is required to increase the pressure to 6 atm.
Answer:
X(EtOH) = 0.0891
X(H₂O) = 0.9109
Explanation:
Given 20% aqueous solution ethanol.
Ethanol => C₂H₅OH (or, EtOH) => molecular weight = 46 g//mole
20% solution by weight = 20 grams EtOH / 100 grams of solution
20 grams EtOH / 100 grams of solution = 20 grams EtOH + 80 grams H₂O
moles EtOH = (20g/46g/mol) = 0.4348 mole
moles H₂O = (80g/18g/mol) = 4.4444 mole
moles EtOH + moles H₂O = 0.4348 + 4.4444 = 4.8792
X(EtOH) = 0.4348/4.8792 = 0.0891
X(H₂O) = 4.4444/4.8792 = 0.9109
∑mole fractions must equal 1.000 => 0.0891 + 0.9109 = 1.000 (check!)
Answer:
The answer is a conductor.
300g because it’s more water to heat, meaning how easy would it be to boil a cup of water? Easy. What about a pool? See what I mean, bigger the area lesser the warmth it gets.