Answer:
cookie monster = 35 cookies
Kramkas = 25 cookies
Mr Syph = 100 cookies
Ms Langberg = 40 cookies
Step-by-step explanation:
Let CM = cookie monster
Let K = Kramkas
Let S = Mr Syph
Let L = Ms Langberg
Write expressions for the info:
K = CM - 10
S = 4K
L = S - 60
Rewrite the expressions in terms of one variable (CM):
K = CM - 10
S = 4K = 4(CM - 10) = 4CM - 40
L = S - 60 = 4(CM - 10) - 60 = 4CM - 40 - 60 = 4CM - 100
CM + K + S + L = 200
⇒ CM + (CM - 10) + (4CM - 40) + (4CM - 100) = 200
⇒ CM + CM + 4CM + 4CM = 200 + 10 + 40 + 100
⇒ 10CM = 350
⇒ CM = 35
⇒ K = CM - 10 = 35 - 10 = 25
⇒ S = 4K = 4 x 25 = 100
⇒ L = S - 60 = 100 - 60 = 40
cookie monster = 35 cookies
Kramkas = 25 cookies
Mr Syph = 100 cookies
Ms Langberg = 40 cookies
Answer:
The equation that represents the motion of the string is given by:
.....[1] where t represents the time in second.
Given that: A = 0.6 cm (distance above its resting position) , k = 1.8(damping constant) and frequency(f) = 105 cycles per second.
Substitute the given values in [1] we get;
or
(a)
The trigonometric function that models the motion of the string is given by:
![y =0.6e^{-1.8t}\cos(210\pi t)](https://tex.z-dn.net/?f=y%20%3D0.6e%5E%7B-1.8t%7D%5Ccos%28210%5Cpi%20t%29)
(b)
Determine the amount of time t that it takes the string to be damped so that ![-0.24\leq y \leq0.24](https://tex.z-dn.net/?f=-0.24%5Cleq%20y%20%5Cleq0.24)
Using graphing calculator for the equation
let x = t (time in sec)
Graph as shown below in the attachment:
we get:
the amount of time t that it takes the string to be damped so that
is, 0.5 sec
Answer:
(1,5)
Step-by-step explanation:
Its gabe because their not 3 miles in one mile miles are silt up by tenths
Answer:
-32/4
Step-by-step explanation:
-8 times 4= -32 put -32 over 4