Answer: Molar mass of Al = 26.98 g/mol
mass of Al = 12 g
mol of Al = (mass)/(molar mass)
= 12/26.98
= 0.4448 mol
According to balanced equation
mol of AlCl3 formed = moles of Al
= 0.4448 mol
Answer: 0.445 mol
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Explanation:
Answer: Freezing point of a solution will be 
Explanation:
Depression in freezing point is given by:

= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte)
= freezing point constant = 
m= molality

Weight of solvent (benzene)= 1480 g =1.48 kg
Molar mass of solute (octane) = 114.0 g/mol
Mass of solute (octane) = 220 g



Thus the freezing point of a solution will be 
Mechanism for oxidation of alkene by KMnO₄ is provided in the attached image: