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lukranit [14]
2 years ago
10

7. Explain how excitatory and inhibitory actions of neurotransmitters are different.

Chemistry
1 answer:
Sauron [17]2 years ago
3 0

In contrast to an inhibitory transmitter, an excitatory transmitter encourages the development of an electrical signal known as an action potential in the receiving neuron.

Depolarization is brought on by excitatory neurotransmitters (decrease in membrane potential). Hyperpolarization is brought on by inhibitory neurotransmitters (increase in membrane potential).

Neurotransmitters fall into two categories: excitatory and inhibitory. While inhibitory neurotransmitters work to stop an action potential, excitatory neurotransmitters function to activate receptors on the postsynaptic membrane and enhance the effects of the action potential.

While inhibitory neurons release neurotransmitters that prevent action potential firing, excitatory neurons release neurotransmitters that cause an action potential to occur in the postsynaptic neuron.

Let's know more about Excitatory & Inhibitory

brainly.com/question/13021637

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kozerog [31]

Answer: A

Explanation:

4 0
3 years ago
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If the ph of a 1.00-in. rainfall over 1400 miles2 is 3.70, how many kilograms of sulfuric acid, h2so4, are present, assuming tha
Natali5045456 [20]

At pH 3.70, H2SO4 can be regarded as being fully dissociated. The dissociation reaction is
H₂SO₄(l) --> 2H⁺(aq) + SO₄²⁻(aq)
Since pH = -log₁₀[H⁺]
[H⁺] = 10^{-pH}
= 10^{-3.7}
[H⁺] = 2 x 10⁻⁴ M
Since there are 2 moles of H⁺ for every mole of H₂SO₄
[H₂SO₄] = 0.5 * [H⁺]
=0.5 * 2 x 10⁻⁴ M
[H₂SO₄] = 1 x 10⁻⁴ M
Convert the amount of rain and the area into SI units
Rain = 1.00 in * 0.0254 m/in
Rain = 0.0254 m
Area = 1600 miles² * 2589988.11 m²/miles²    = 4.661 x 10⁹  m²

Calculate the volume of water

Volume = Rain * Area
=0.0254 m * 4.661 x 10⁹
Volume = 1.184 x 10⁸ m³

Calculate the number of kilo moles of H₂SO₄

kilo moles H₂SO₄ = [H₂SO₄] * Volume
=1.0 x 10⁻⁴ M * 1.184 x 10⁸ m³
kilo moles H₂SO₄ = 11,839 k mole

Calculate the mass of H₂SO₄

mass H₂SO₄ = kilo moles H₂SO₄ * MW H₂SO₄
= 11839 k mol * 98.07848 kg/kmol
mass H₂SO₄ = 1.16 x 10⁶ kg H₂SO₄

5 0
3 years ago
Which two structures would provide a positive identification of a animal cell under a microscope
babunello [35]
Lack of cell walls no chloroplasts...hoped that helped
4 0
4 years ago
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Consider the general reaction: 2 A + b B → c C and the following average rate data over a specific time period \Delta t: - \frac
lawyer [7]

Answer:

c = 4

Explanation:

In general, for the reaction

       a A     +    b B     ⇒ c C   +    d D

the rate is given by:

rate = - 1/a ΔA/Δt = - 1/b ΔB/Δt = + 1/c ΔC/Δt = + 1/d ΔD/Δt

this is done so as to express the rate in a standarized way which is the same to all the reactants and products irrespective of their stoichiometric coefficients.

For this question in particular we know the coefficient of A and need to determine the coefficient c.

- 1/2 ΔA/Δt = + 1/c ΔC/Δt

- 1/2 (-0.0080 ) = + 1/c ( 0.0160 mol L⁻¹s⁻¹ )

0.0040 mol L⁻¹s⁻¹  c = 0.0160 mol L⁻¹s⁻¹

∴ c = 0.0160 / 0.0040 = 4

7 0
3 years ago
What number of cations is present in 1.17g of sodium chloride ?
taurus [48]

Answer:

1.2 × 10^22 atoms.

Explanation:

Firstly, cations refers to the positively charged atom in the ionic compound, which is Na+.

Given the mass of NaCl as 1.17g, the number of moles of NaCl can be calculated this:

Molar mass of NaCl = 23 + 35.5

= 58.5g/mol

Mole = mass/molar mass

Mole = 1.17/58.5

Mole = 0.02moles

Using Avagadro's number, 6.022 × 10^23 atoms of Na+ are in 1 mole of NaCl.

In 0.02 moles of NaCl, there are 0.02 × 6.022 × 10^23 of Na+

0.1204 × 10^23 atoms

1.2 × 10^22 atoms of Na+ (cation)

5 0
3 years ago
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