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frozen [14]
2 years ago
7

Ch4+202==>c02+302 what type of chemical reaction

Chemistry
1 answer:
n200080 [17]2 years ago
4 0

Answer:

First of all, the equation is typed wrong so it can easily be misinterpreted

Ethane (CH4) + Oxygen gas (O2) would give us Carbon Dioxide (CO2) and WATER (H2O)

CH4 + 2O2 -----> CO2 + 2H2O

And this is a combustion reaction since we have oxygen as a reactant and carbon dioxide and water as products.

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The complementary base sequence to GTAGCT is:_______.A) CATCGA.B) ACGATC.C) GCAGTA.D) AGTCGA.E) None of the above
IceJOKER [234]

Answer:none of the above

Explanation:

8 0
2 years ago
You need to determine the specific gravity of a sample. After putting the sample on a lab scale, you know it has a mass of 85 gr
BlackZzzverrR [31]

Answer:

Specific gravity of the sample = 8.947

Explanation:

Specific gravity of a substance is defined as the density of that substance divided by the density of water.

Density of water = 1000g/l

Density of substance = mass/volume

= 85/9.5 x 10^-3

= 8947.37 g/l

SG = 8947.37/1000

= 8.947

3 0
2 years ago
Which change to an object would double its kinetic energy?
Rina8888 [55]

Answer:

Increasing its mass to twice its original value

Explanation:

Pls mark me brainliest

4 0
3 years ago
Which substance is the most alkaline?<br>a. blood<br>b. orange juice<br>c. ammonia<br>d. milk​
AnnyKZ [126]

Answer:

c. ammonia

Explanation:

Ammonia is a base, so it is most alkaline.

7 0
3 years ago
For the reaction below, Kp = 1.59 at 100°C. If 1.0 g of SrCO3 is placed in an empty 5.00 L reactor and allowed to reach equilibr
Sergio [31]

Answer:

p_{CO_2}^{eq}=1.59atm

Explanation:

Hello, in this case, one could consider the undergoing chemical reaction as:

SrCO_3(s)\rightleftharpoons SrO(s)+CO_2(g)

Thus, since 1.0 g of strontium carbonate is placed, the equilibrium equation takes the following form, excluding the solid-stated species and considering just the carbon dioxide as it is gaseous:

Kp=p_{CO_2}^{eq}=1.59atm

Hence, since at the beginning there is no carbon dioxide, its pressure at equilibrium equals Kp:

Kp=p_{CO_2}^{eq}=1.59atm

Which was clearly defined above.

Best regards.

8 0
3 years ago
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