4 goes into 36 9 times and 36-36 is zero. Bring down the 2 and at a zero to it so it will be 20. Finally, 4 goes into 20 5 times. Your answer is 9.5
Answer:
a=−3
Step-by-step explanation:
Let's solve your equation step-by-step.
3(4a+4)=3a+8a+1+8
Step 1: Simplify both sides of the equation.
3(4a+4)=3a+8a+1+8
(3)(4a)+(3)(4)=3a+8a+1+8(Distribute)
12a+12=3a+8a+1+8
12a+12=(3a+8a)+(1+8)(Combine Like Terms)
12a+12=11a+9
12a+12=11a+9
Step 2: Subtract 11a from both sides.
12a+12−11a=11a+9−11a
a+12=9
Step 3: Subtract 12 from both sides.
a+12−12=9−12
a=−3
Answer:
a=−3
Answer:
The products of AB and BA is given by
AB=![\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D21%26-6%5C%5C%209%263%5Cend%7Barray%7D%5Cright%5D)
BA=![\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%26-1%5C%5C-18%2615%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given the matrices A=
and
B=![\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-1%5C%5C-3%260%5Cend%7Barray%7D%5Cright%5D)
To find the product AB and BA
AB=![\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right] \left[\begin{array}{cc}1 & -1\\-3 &0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%26-5%5C%5C-3%26-4%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%20%26%20-1%5C%5C-3%20%260%5Cend%7Barray%7D%5Cright%5D)
![=\left[\begin{array}{cc}6+15& -6+0\\-3+12&3-0\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%2B15%26%20-6%2B0%5C%5C-3%2B12%263-0%5Cend%7Barray%7D%5Cright%5D)
Therefore the product of AB is
AB=![\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D21%26-6%5C%5C%209%263%5Cend%7Barray%7D%5Cright%5D)
BA=
![\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%26-5%5C%5C-3%26-4%5Cend%7Barray%7D%5Cright%5D)
![=\left[\begin{array}{cc}6+3& -5+4\\-18+0&15+0\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%2B3%26%20-5%2B4%5C%5C-18%2B0%2615%2B0%5Cend%7Barray%7D%5Cright%5D)
Therefore the product of BA is
BA=![\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%26-1%5C%5C-18%2615%5Cend%7Barray%7D%5Cright%5D)
The products of AB and BA is given by
AB=![\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D21%26-6%5C%5C%209%263%5Cend%7Barray%7D%5Cright%5D)
BA=![\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%26-1%5C%5C-18%2615%5Cend%7Barray%7D%5Cright%5D)
Answer:
ninety and one hundred twenty-five thousandths
Step-by-step explanation:
IS THIS IT.....