The molecular geometry of both F2 and HF is linear.There are only two atoms which are covalently bonded and thus, the bonding scheme with the atoms looks like this;
F --- F
H---F
So, both are linear.
Answer:
Polar covalent bond
Explanation:
When two atoms of unequal electro- negativity comes together to form bonds , there is unequal sharing of electrons between them , one of them acquaring partial positive and partial negative charge . Then they make bond due to mutual attraction.
Bond formation in HCl in gaseous state is an example .
For each revolution, the satellite covers the circumference
of its orbit.
The circumference of a circle is (pi) x (diameter).
Since the satellite is 22,500 miles from the center, that number
is the radius of the circle. The diameter is 45,000 miles.
The circumference is (pi) x (45,000 miles) = 141,372 miles
The satellite's average speed is 141,372 miles per day, or
(141,372 / 24) = 5,890 miles per hour
relative to the center of the Earth.
1) In any collision the momentum is conserved
(2*m)*(vo) + (m)*(-2*vo) = (2*m)(v1') + (m)(v2')
candel all the m factors (because they appear in all the terms on both sides of the equation)
2(vo) - 2(vo) = 2(v1') + (v2') => 2(v1') + v(2') = 0 => (v2') = - 2(v1')
2) Elastic collision => conservation of energy
=> [1/2] (2*m) (vo)^2 + [1/2](m)*(2*vo)^2 = [1/2](2*m)(v1')^2 + [1/2](m)(v2')^2
cancel all the 1/2 and m factors =>
2(vo)^2 + 4(vo)^2 = 2(v1')^2 + (v2')^2 =>
4(vo)^2 = 2(v1')^2 + (v2')^2
now replace (v2') = -2(v1')
=> 4(vo)^2 = 2(v1')^2 + [-2(v1')]^2 = 2(v1')^2 + 4(v1')^2 = 6(v1')^2 =>
(v1')^2 = [4/6] (vo)^2 =>
(v1')^2 = [2/3] (vo)^2 =>
(v1') = [√(2/3)]*(vo)
Answer: (v1') = [√(2/3)]*(vo)
