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3 years ago

What should Isla write in the areas marked A, B, and C?

Physics

2 answers:

NISA [10]3 years ago

6 0

Answer:

Radio waves: have a longer wavelength

X-rays: have a higher frequency

Both: they travel at the same speed

Explanation:

Missing part of the question:

"Isla made a diagram to compare x-rays and radio waves. what should isla write in the areas marked a, b, and c?"

X-rays and radio waves are both types of electromagnetic waves.

Electromagnetic waves consist of oscillations of the electric and the magnetic fields in a plane perpendicular to the direction of propagation the wave.

All electromagnetic waves travel in a vacuum always at the same speed, the speed of light:

$c=3.0\cdot 10^8 m/s$

Electromagnetic waves are also classified into 7 different types, according to their wavelength/frequency. From longest to shortest wavelength (and from lowest to highest frequency, since frequency is inversely proportional to wavelength), they are:

Radio waves (>1 m)

Microwaves (1 mm - 1 m)

Infrared (750 nm - 1 mm)

Visible light (380 nm - 750 nm)

Ultraviolet (10 nm - 380 nm)

X-rays (0.01 nm - 10 nm)

Gamma rays (<0.01 nm)

Therefore, the correct matches are:

Radio waves: have a longer wavelength

X-rays: have a higher frequency

Both: they travel at the same speed

igomit [66]3 years ago

5 0

Answer:

A: Has a higher frequency

B: Travels at the same speed

C: Has a longer wavelength

Got on quiz

Explanation:

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3 years ago

What is the gravitational potential energy of a 15.0kg object that is 5.00m above the ground relative to a point 8.00m above the

Licemer1 [7]

Explanation:

an object's gravitational potential energy Eg is m×g×h where:

m=mass

g=9.8m/s²

h=height relative to the closest object below it (because it cannot potentially fall through it

so Eg = 15×9.8×5=735J

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1 year ago

In physics what does 7.56 × 5.746 equal ?

lapo4ka [179]

Answer:

43.43

Explanation:

5.746 x 7.56 = 43.43976

As the least number of desimal is two so our awnser should contain two digits after the decimal point.

Ans: 43.43.

7 0

3 years ago

Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid

Korolek [52]

Answer:

$z= 2.5 \ m$

$z = (1 \ m , 4 \ m )$

Explanation:

From the question we are told that

Their distance apart is $d = 5.00 \ m$

The wavelength of each source wave $\lambda = 6.0 \ m$

Let the distance from source A where the construct interference occurred be z

Generally the path difference for constructive interference is

$z - (d-z) = m \lambda$

Now given that we are considering just the straight line (i.e points along the line connecting the two sources ) then the order of the maxima m = 0

$z - (5-z) = 0$

=> $2 z - 5 = 0$

=> $z= 2.5 \ m$

Generally the path difference for destructive interference is

$|z-(d-z)| = (2m + 1)\frac{\lambda}{2}$

=> $|2z - d |= (0 + 1)\frac{\lambda}{2}$

=> $|2z - d| =\frac{\lambda}{2}$

substituting values

$|2z - 5| =\frac{6}{2}$

=> $z = \frac{5 \pm 3}{2}$

$z = \frac{5 + 3}{2}$

$z = 4\ m$

and

$z = \frac{ 5 -3 }{2}$

=> $z = 1 \ m$

=> $z = (1 \ m , 4 \ m )$

7 0

3 years ago

We know the frequency range of certain sounds are: 400-560 Hz, what are the ranges of wavelength in meters when the signal trans

Ksivusya [100]

Answer:

Range of wavelength will be $5.35\times 10^5m$ to $7.5\times 10^5m$

Explanation:

We have given range of frequency is 400-560 Hz

Speed of the light $c=3\times 10^8m/sec$

We have to find the range of the wavelength of signal transmitted

Ween know that velocity is given by $v=\lambda f$ , here $\lambda$ is wavelength and f is frequency

So for 400 Hz frequency wavelength will be $\lambda =\frac{c}{f}=\frac{3\times 10^8}{400}=7.5\times 10^5m$

And wavelength for frequency 560 Hz $\lambda =\frac{c}{f}=\frac{3\times 10^8}{560}=5.35\times 10^5m$

So range of wavelength will be $5.35\times 10^5m$ to $7.5\times 10^5m$

8 0

3 years ago