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Leya [2.2K]
3 years ago
15

What should Isla write in the areas marked A, B, and C?

Physics
2 answers:
NISA [10]3 years ago
6 0

Answer:

Radio waves: have a longer wavelength

X-rays: have a higher frequency

Both: they travel at the same speed

Explanation:

Missing part of the question:

"Isla made a diagram to compare x-rays and radio waves. what should isla write in the areas marked a, b, and c?"

X-rays and radio waves are both types of electromagnetic waves.

Electromagnetic waves consist of oscillations of the electric and the magnetic fields in a plane perpendicular to the direction of propagation the wave.

All electromagnetic waves travel in a vacuum always at the same speed, the speed of light:

c=3.0\cdot 10^8 m/s

Electromagnetic waves are also classified into 7 different types, according to their wavelength/frequency. From longest to shortest wavelength (and  from lowest to highest frequency, since frequency is inversely proportional to wavelength), they are:

Radio waves (>1 m)

Microwaves (1 mm - 1 m)

Infrared (750 nm - 1 mm)

Visible light (380 nm - 750 nm)

Ultraviolet (10 nm - 380 nm)

X-rays (0.01 nm - 10 nm)

Gamma rays (<0.01 nm)

Therefore, the correct matches are:

Radio waves: have a longer wavelength

X-rays: have a higher frequency

Both: they travel at the same speed

igomit [66]3 years ago
5 0

Answer:

A: Has a higher frequency

B: Travels at the same speed

C: Has a longer wavelength

  Got on quiz

Explanation:

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Rina8888 [55]

The force required is 319 N

Explanation:

The force of static friction is a force that acts an object on a surface, when this object is pushed by another force to put it in motion. The direction of the force of friction is opposite to the direction of the force of push, and its value increases as the force of push increases, up to a maximum value given by:

F_f = \mu W

where

\mu is the coefficient of friction

W is the weight of the object

Therefore, in order to put the object in motion, the force applied must be greater than this value.

For the pile of leaves in this problem, we have:

\mu = 0.55 (coefficient of friction)

W=580 N (weight of the leaves)

Substituting, we find:

F=(0.55)(580)=319 N

Learn more about force of friction:

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3 years ago
I NEED HELP PLEASE, THANKS! Describe each Newton Law. :)
Alex

Explanation:

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2nd- states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it. (most important law)

3rd- states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. (law of action/reaction)

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What is the relationship between temperature and height in the troposphere ,stratosphere,mesophere,thermosphere,exosphere
Soloha48 [4]

In general the higher we go the cooler it becomes . temperature fall continues within the lowermost layer of our atmosphere, known as the troposphere. Above the troposphere, the stratosphere exists and in this region the temperature increases with an increase in altitude. The mesosphere is the part of the atmosphere that lies above the stratosphere. In this region, the temperature falls with an increase in altitude. And finally as we continue rising up, we reach the thermosphere, where the temperature increases with increased altitude.

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The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actu
Juliette [100K]

\orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTION}}}}}}}

The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?

{\bold{\blue{GIVEN}}}

REFRACTIVE INDEX = 1.3

APPARENT DEPTH = 7.7 cm

{ \bold{\green{To  \: Find}}}

REAL DEPTH OF THE OBJECT.

{\red{FORMULA   \:  \: USED }}

Reflective  \:  Index  =  \frac{Real \:  Depth}{Apparent  \: Depth }

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Refractive Index = 1.3

Apparent Depth = 7.7 cm

Putting the values in the formula:-

Reflective  \:  Index  =  \frac{Real \:  Depth}{Apparent  \: Depth }  \\  \\ 1.3 =  \frac{Real \:  Depth}{7.7 \: cm}  \\ \\  1.3 \times 7.7 = Real \:  Depth \\  \\ 10.01 \:  \: cm = Real \:  Depth

3 0
2 years ago
What is potential difference​
lisabon 2012 [21]

Answer:

VOLTAGE

Explanation:

Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit. ... A potential difference of one Volt is equal to one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit

5 0
3 years ago
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