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3 years ago

What should Isla write in the areas marked A, B, and C?

Physics

2 answers:

NISA [10]3 years ago

6 0

Answer:

Radio waves: have a longer wavelength

X-rays: have a higher frequency

Both: they travel at the same speed

Explanation:

Missing part of the question:

"Isla made a diagram to compare x-rays and radio waves. what should isla write in the areas marked a, b, and c?"

X-rays and radio waves are both types of electromagnetic waves.

Electromagnetic waves consist of oscillations of the electric and the magnetic fields in a plane perpendicular to the direction of propagation the wave.

All electromagnetic waves travel in a vacuum always at the same speed, the speed of light:

$c=3.0\cdot 10^8 m/s$

Electromagnetic waves are also classified into 7 different types, according to their wavelength/frequency. From longest to shortest wavelength (and from lowest to highest frequency, since frequency is inversely proportional to wavelength), they are:

Radio waves (>1 m)

Microwaves (1 mm - 1 m)

Infrared (750 nm - 1 mm)

Visible light (380 nm - 750 nm)

Ultraviolet (10 nm - 380 nm)

X-rays (0.01 nm - 10 nm)

Gamma rays (<0.01 nm)

Therefore, the correct matches are:

Radio waves: have a longer wavelength

X-rays: have a higher frequency

Both: they travel at the same speed

igomit [66]3 years ago

5 0

Answer:

A: Has a higher frequency

B: Travels at the same speed

C: Has a longer wavelength

Got on quiz

Explanation:

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One mol of a perfect, monatomic gas expands reversibly and isothermally at 300 K from a pressure of 10 atm to a pressure of 2 at

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Answer:

Explanation:

Given

1 mole of perfect, monoatomic gas

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$P_f$ =Final Pressure

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Therefore q=39.64 J

(b)if the gas expands by the same amount again isotherm-ally and irreversibly

work done is $=P\Delta V$

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3 years ago

A 70.0-kg person throws a 0.0480-kg snowball forward with a ground speed of 33.5 m/s. A second person, with a mass of 55.0 kg, c

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Answer:

The final velocity of the thrower is $\bf{3.88~m/s}$ and the final velocity of the catcher is $\bf{0.029~m/s}$ .

Explanation:

Given:

The mass of the thrower, $m_{t} = 70~Kg$ .

The mass of the catcher, $m_{c} = 55~Kg$ .

The mass of the ball, $m_{b} = 0.0480~Kg$ .

Initial velocity of the thrower, $v_{it} = 3.90~m/s$

Final velocity of the ball, $v_{fb} = 33.5~m/s$

Initial velocity of the catcher, $v_{ic} = 0~m/s$

Consider that the final velocity of the thrower is $v_{ft}$ . From the conservation of momentum,

$&& m_{t}v_{ft} + m_{b}v_{fb} = (m_{t} + m_{b})v_{it}\\&or,& v_{ft} = \dfrac{(m_{t} + m_{b})v_{it} - m_{b}v_{fb}}{m_{t}}\\&or,& v_{ft} = \dfrac{(70 + 0.0480)(3.90) - (0.0480)(33.5)}{70}\\&or,& v_{ft} = 3.88~m/s$

Consider that the final velocity of the catcher is $v_{fc}$ . From the conservation of momentum,

$&& (m_{c} + m_{b})v_{fc} = m_{b}v_{it}\\&or,& v_{fc} = \dfrac{m_{b}v_{it}}{(m_{c} + m_{b})}\\&or,& v_{fc} = \dfrac{(0.048)(33.5)}{(55.0 + 0.0480)}\\&or,& v_{fc} = 0.029~m/s$

Thus, the final velocity of thrower is $3.88~m/s$ and that for the catcher is $0.029~m/s$ .

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