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3 years ago

Simplify

Mathematics

1 answer:

Schach [20]3 years ago

8 0

$2x + 7y + 3x + 4y$

$(2x+3x)+(7y-4y)
 
$ $Gather \ like \ terms$

$5x+11y$

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Can someone help me on this one pls

frozen [14]

Answer:

d=5

Step-by-step explanation:

6x = 5

d = 6x

if 6x = 5 then d would also equal 5

3 0

3 years ago

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If $a$, $b$, $c$, and $d$ are replaced by four distinct digits from $1$ to $9$, inclusive, then what's the largest possible valu

Alexxx [7]

Answer:

Step-by-step explanation:

for the value of difference to be largest, the minuend should be maximum(most possibly) and the subtrahend should be minimum

[in A-B=X, A is minuend and B is subtrahend ]

so, $a.b should be maximum. as there is a condition that 4 digits should be distinct, the product will be maximum if we choose 2 maximum valued numbers from the given numbers. so, one of them should be 9 and the other should be 8.

therefore, $a.b=9*8=72

as mentioned above, c.d$ should be minimum. this will be possible only when we choose 2 minimum valued numbers from the given numbers. so, one of them should be 1 and the other should be 2.

therefore, c.d$ = 1*2 = 2

hence, the difference = 72-2 = 70

thus, the largest possible value of the difference $a.b - c.d$ = 70

7 0

3 years ago

Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have one digit followed

Alekssandra [29.7K]

Answer: The required number of passwords that can be created is 175760.

Step-by-step explanation: Given that a company needs temporary passwords for the trial of a new payroll software.

Each password will have one digit followed by three letters and the letters can be repeated.

We are to find the number of passwords that can be created using this format.

For the one digit in the password, we have 10 options, 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Since there are 26 letters in English alphabet and letters can be repeated, so the number of options for 3 letters is

26 × 26 × 26 = 17576.

Therefore, the total number of ways in which passwords can be created using the given format is

$n=9\times17576=175760.$

Thus, the required number of passwords that can be created is 175760.

3 0

3 years ago

What is the solution to the equation startroot 2n+28 endroot -4 startroot n endroot =0 n=2 n=4 n=7 n=14

GuDViN [60]

The answer is 7 because yeah

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3 years ago

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Frank marry and seth shared some sweets in the ratio 4:5:7 seth got 18 more sweets than frank work out the total number of sweet

Alina [70]

Answer: 96

seth got 18 more than frank

in terms of ratio he got 3 more than frank

this means that 3 is equal to 18

so we find the whole ratio to fing the total

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3 years ago