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lorasvet [3.4K]
3 years ago
6

Find the value of x.

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
6 0

Answer:

your answer will be<u> X=80</u>

Step-by-step explanation:

x+42+58=180\\\\x=180-58-42\\\\x=80

<u>hope this helps u have a nice day </u>

Elodia [21]3 years ago
6 0

Answer:

80°

Step-by-step explanation:

58°+42°+x°=180°

100°+x°=180°

100°-100° + x° = 180°-100°

x° = 80°

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Steve has a regular deck of playing cards. He wants to know the probability of pulling two clubs from the deck in a row without
Murrr4er [49]
Es la D por que eso ya lo hice yo
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3 years ago
I need help on this
Naily [24]

Answer:x=90° y=58° z=32°

Step-by-step explanation:

x=90

y=180-(90+32) sum of angles in a triangle is 180

y=58

y+90+z=180 they are supplementary

58+90+z=180

148+z=180

z=180-148

z=32

5 0
4 years ago
How many times greater is 10 cubic yards than 5 cubic yard? Complete the equation
monitta

Answer:

2 times

Step-by-step explanation:

10 / 5 = 2

   or

5 x 2 = 10

so 10 is 2 times greater than 5

8 0
3 years ago
You start with a penny which doubles each day for 30 days. How much money would you have after 30 days?
Radda [10]

Answer:

$555,765.76

Step-by-step explanation:

1

2

4

8

16

32

64

128

256

512

1024

2048

4096

8192

16282

32564

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6 0
3 years ago
If f(x)=sinx 2x 1 and g is the inverse function of f
Bingel [31]

The value of the derivative of the function g(x) at x = 1 will be 1/3. Then the correct option is A.

<h3>What is an inverse function?</h3>

A function that may convert into another function is known as an inverse function or anti-function.

If the function is f(x) = sinx + 2x + 1.

Then the derivative of an inverse function g(x) of a function f(x) at a given value (a) will be

\rm g'(a) = \dfrac{1}{f'(g(a))}

The derivative of f(x) will be

f'(x) = cos x + 2

Then the given value of a will be

a = 1

g(x) = f⁻¹(x)

put x = 0, then we have

f(0) = sin 0 + 2(0) + 1

f(0) = 1

Put x = 1, in the function f⁻¹(x). Then we have

f⁻¹(1) = 0

and

g(1) = 0

Then put a = 1, then we have

\rm g'(a) = \dfrac{1}{f'(g(a))}\\\\g'(1) = \dfrac{1}{f'(g(1))}\\\\g'(1) = \dfrac{1}{f'(0)}\\\\g'(1) = \dfrac{1}{\cos 0 + 2}\\\\g'(1) = \dfrac{1}{1+2}= \dfrac{1}{3}

More about the inverse function link is given below.

brainly.com/question/2541698

#SPJ4

8 0
2 years ago
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