What does one prolonged blast emitted by boat a using an efficient sound producing device indicate?

1 answer:

3 0

A single prolonged blast emitted by a boat using an efficient sound producing devices indicates that the boat is leaving the dock. It may also be used to indicate that the boat is moving and for alarming other vessels, but in this case, one prolonged blast is followed by two short blasts, in two minutes of time.

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What is the frequency of a sound wave having a velocity of 341 meters/second and a wavelength of 0.8 meters?

Brums [2.3K]

We know, Frequency = speed / wavelength
f = 341 / 0.8
f = 426.25 Hz

In short, Your Answer would be 426.25 Hz

Hope this helps!

6 0

3 years ago

Read 2 more answers

If an object has no acceleration, can you conclude that no forces are exerted on it

MrMuchimi

No. It has no acceleration, which just means that the forces acting on it are equal and opposite, not that there are no forces exerted on it.

But if you're talking about the resulting Net Force, then yes you can conclude there is no Net Force acting on an object with no acceleration.

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3 years ago

The relationship between energy (E), power (P), and time (t) is

NemiM [27]

Answer:

The avarage power of the body is 96.898 watts.

Explanation:

We must notice that given definition of power implies a constant consumption of energy, so that we should assume that energy consumption is constant. A Calorie is equal to 4186 joules. If we know that $E = 2000\,Cal$ and $t = 1\,day$ , the power of body, measured in watts, is:

$P = \frac{(2000\,Cal)\cdot \left(4186\,\frac{J}{Cal} \right)}{(1\,day)\cdot \left(24\,\frac{h}{day} \right)\cdot \left(3600\,\frac{s}{h} \right)}$

$P = 96.898\,W$

The avarage power of the body is 96.898 watts.

3 0

4 years ago

) Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) . What are (a)

natali 33 [55]

To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.

The vector product between the Force and the radius allows us to obtain the torque, in this way,

$\tau = \vec{F} \times \vec{r}$